2. 120 kN 120 kN 150 kN E B D F 6 m m 6 m m 4 m- 21 E = 200 Gpa I = 500 (106) mm4
2. 120 kN 120 kN 150 kN E B D F 6 m m 6 m m 4 m- 21 E = 200 Gpa I = 500 (106) mm4
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
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determine the reactions and draw the shear moment diagram by using Three moment equation examples
![2.
120 kN
120 kN
150 kN
A
E
В
D
F
6 m
4 m
6 m
-4 m-
4 m-
21
E = 200 Gpa
I = 500 (106) mm4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb408e23-2738-4395-ae6c-0414a6a34426%2F7a58c14f-82b6-4fd3-b86b-bfcc609cf673%2Fjfyl69k_processed.png&w=3840&q=75)
Transcribed Image Text:2.
120 kN
120 kN
150 kN
A
E
В
D
F
6 m
4 m
6 m
-4 m-
4 m-
21
E = 200 Gpa
I = 500 (106) mm4
![3. Settlement of 20mm at support B.
A
B
D
-8 m
-8 m-
8 m
E = 70 GPa
I = 800 (106) mm4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb408e23-2738-4395-ae6c-0414a6a34426%2F7a58c14f-82b6-4fd3-b86b-bfcc609cf673%2Fe4ws2uo_processed.png&w=3840&q=75)
Transcribed Image Text:3. Settlement of 20mm at support B.
A
B
D
-8 m
-8 m-
8 m
E = 70 GPa
I = 800 (106) mm4
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