For the truss shown below, determine the forces in members UP, QL, JK. Assign a negative valuefor tensile forces and positive value for compressive forces. "Q R SUN.H`ADEFGP1P1P2P2P2P1P1L2L2L2 P1P2L1L227 kN48 kN5 m3m3mUP = kN Use 3 decimal placesQL = kN Use 3 decimal placesJK = kN Use 3 decimal places%3D

Answered: Image /qna-images/answer/1ca6fef1-f4e9-4bf7-8955-e0b56a934aef.jpg

Answered: Q R S LU M H. `A E F G H P1 P1 P2 P2 P2…

Engineering

Civil Engineering

Q R S LU M H. `A E F G H P1 P1 P2 P2 P2 P1 L2 L2

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Two cylindrical rods, one of steel and the other of brass, are joined at C and restrained by rigid supports at A and E. For the loading shown and knowing that E, = 200 GPa and Eb = 105 GPa, determine the deflection of point C. Sc A um →>> Dimensions in mm 120 180130- Steel B 65 KN 40-mm diam. D Brass 120 E 50 KN 30-mm diam.
Question 1) F=22 kN single load, M=24 kN.m moment and w=5 kN/m distributed load act on the beam whose loading condition is given in the figure. The length L is also given as L=4 m. The cross-sectional properties of the beam are; body height y g = 203 mm , body thickness x g = 19 mm, flange width x f = 172 mm , flange height y f =16 mm. Point E on the section is located just below the flange-body junction. It is desired to determine the stress state in the section taken from the B level of the beam. According to this; Question 1-E) Find the y distance of the section center with respect to the axis passing through the base of the section. ( Write your result in mm .) Question 1-F) section. (Do your operations by converting the lengths to meters. Take at least 4 digits for the decimal part of your result and use the expression E for the decimal part. Write it as 5E-3 instead of 0.005 .) Find the moment of inertia of the beam a section taken from point B of the beam; Find the normal stress…
I need right solution with clear calculation. Thank you
Q3: Find the magnitude, location and slope of the resultant of the force system shown below. k=30 &N た100以 53° B 30 -50 &N 3 m 1 m a4 アブァア

Compute for the y-component of the force F2 = 212.5 N at 0₁ = 17.0. 310 320 250 240 0€Z ozz 012 1 FR 330 340 350 002 061 FORCE 180 081 0₂ 04 TABLE 091 <-8- 091 140 30 1 120 110 100
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determin the x and y conponents of the reactions A and B. For reaction B the solution shoukd be in kN units. Make sure the moment of B is included. everything must have units please. Need only a handwritten solution only (not a typed one).
For F=500 N and 0 =30 deg. y F 30° 500 N The Y- component of the resultant force is equal to 1000 N The X-component of the resultant force is equal to 500 N The Y- component of the resultant force is equal to zero The X-component of the resultant force is equal to zero
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So VDL should belong to upward force instead of downward force side. And the sign should be negative instead of positive. Can you make it more clear ?