For the beam shown in the figure below • Calculate the reaction forces. • Express the internal shear force and moment in the beam as functions of x for 0 < x < a and a < x< a + b • Draw the shear and moment diagrams q_0 = 4 kN/m a = 4 m b = 1 m F = 5 kN F a b

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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### Beam Analysis Problem

For the beam shown in the figure below:

- **Calculate the reaction forces.**
  
- **Express the internal shear force and moment in the beam as functions of \(x\) for \(0 \leq x \leq a\) and \(a \leq x \leq a + b\).**

- **Draw the shear and moment diagrams.**

**Given Parameters:**

- \( q_0 = 4 \, \text{kN/m} \) (Triangular distributed load)
- \( a = 4 \, \text{m} \)
- \( b = 1 \, \text{m} \)
- \( F = 5 \, \text{kN} \) (Point load at the end of the beam)

**Beam Diagram Description:**

The beam rests on two supports. The left support is a fixed end, while the right support is a roller. Over the length \(a\), the beam is subjected to a triangular distributed load beginning from \(q_0\) at the left support and tapering to zero at the right end of \(a\). At the end of length \(a + b\), a point load \(F\) is applied downward.
Transcribed Image Text:### Beam Analysis Problem For the beam shown in the figure below: - **Calculate the reaction forces.** - **Express the internal shear force and moment in the beam as functions of \(x\) for \(0 \leq x \leq a\) and \(a \leq x \leq a + b\).** - **Draw the shear and moment diagrams.** **Given Parameters:** - \( q_0 = 4 \, \text{kN/m} \) (Triangular distributed load) - \( a = 4 \, \text{m} \) - \( b = 1 \, \text{m} \) - \( F = 5 \, \text{kN} \) (Point load at the end of the beam) **Beam Diagram Description:** The beam rests on two supports. The left support is a fixed end, while the right support is a roller. Over the length \(a\), the beam is subjected to a triangular distributed load beginning from \(q_0\) at the left support and tapering to zero at the right end of \(a\). At the end of length \(a + b\), a point load \(F\) is applied downward.
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