Solve like the example REFER TO THESE WORKED EXAMPLES AS YOU ATTEMPT TO SOLVE YOUR PROBLEM:At a pressure of 405 kPa, the volume of a gas is 6.00 cm³.Assuming the temperature remains constant, what will be the newpressure when the volume of a gas decreases to 4.0 cm³?P1 = 405 kPaExample:V1 = 6.0 cm³V2=4.0 cm³Provide written reasoning here.Why does your answer make sense?1.Identify givens and the unknown.Convert all temperatures to Kelvin.2.3. Rearrange the equation if you'd like P₁V₁= P₂V₂Substitute values into the equation.5. Solve for the unknown.Check your answer against theory.Since Boyle's Law is an indirect relationship, adecrease in V and an increase in P makes sense.JhyP1 * V1Show calculation work here.6.0 cm² =405 kPa405 kPa 6.0 cm² =P2 * V2P2 4,0 cm³P2 4.0 cm³4.0 cm³607.5 kPa = P2610 kPa = P2A balloon contains 4 L of air at 100 kPa.You squeeze it to a volume of 1 L.What is the new pressure of air inside the balloon? Gas LawsBoyle's LawAt a pressure of 405 kPa, the volume of a gas is 6.00 cm³. VAssuming the temperature remains constant, what will be thenew pressure when the volume of a gas decreases to 4.0 cm³?Prediction using theory: The final pressure will be greater than 405 kPa.4-Identify givers and the unknown.Convert all temeratures to ketvin.D. Rearrange the equation if you'd like4. Substitute values into the equation.5. Solve for the unknown.6. Check your answer against theory.P1 = 405 kPaP2 = 1₂3V1 = 6.00chv2 = 4.00cm²³V2P₁V₁=P₂₂RY2 22405 kPa 6.000m4.00 cm³кра607.5 KR6024304.00

Answered: Image /qna-images/answer/99ab0334-51b2-4dc9-8d9e-740f6653b65b.jpg

2. 1. Identify givens and the unknown. Convert all temperatures to Kelvin. 3. Rearrange the equation if you'd like. 4. Substitute values into the equation. 5. Solve for the unknown. 6. Check your answer against theory. Provide written reasoning here. Why does your answer make sense? P₁V₁ = P₂V₂ A balloon contains 4 L of air at 100 kPa. You squeeze it to a volume of 1 L. What is the new pressure of air inside the balloon? Show calculation work here

2. 1. Identify givens and the unknown. Convert all temperatures to Kelvin. 3. Rearrange the equation if you'd like. 4. Substitute values into the equation. 5. Solve for the unknown. 6. Check your answer against theory. Provide written reasoning here. Why does your answer make sense? P₁V₁ = P₂V₂ A balloon contains 4 L of air at 100 kPa. You squeeze it to a volume of 1 L. What is the new pressure of air inside the balloon? Show calculation work here

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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