2, The differential equation of a continuous-time LTI system are given as below: d'y(t) dy(t) +3 +2 y(t) = e(t) dt dt? y(0) = 2 y'(0-) = 2 e(t) = 2e"E(t) -3t initial conditions the exciting signals : Find : (1) Zero-input response t; (2) Zero-state response t; (3) complete response r t ;

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2, The differential equation of a continuous-time LTI system are given as
below:
d?y(t)
dy(t)
-+2 y(t) = e(t)
dt
+3
dt?
e(t) = 2e"E(t)
-3t
y(0~) = 2
y'(0") = 2
initial conditions
the exciting signals :
Find : (1) Zero-input response a
t
(2) Zero-state response t ;
(3) complete response r t ;
Transcribed Image Text:2, The differential equation of a continuous-time LTI system are given as below: d?y(t) dy(t) -+2 y(t) = e(t) dt +3 dt? e(t) = 2e"E(t) -3t y(0~) = 2 y'(0") = 2 initial conditions the exciting signals : Find : (1) Zero-input response a t (2) Zero-state response t ; (3) complete response r t ;
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