2) Find the Laurent series for 4z √(z) = (z - 1)(z-3)2 centered at z = 3. Over what annulus in the complex plane is this series expansion valid?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 49E
Question
2) Find the Laurent series for
4z
√(z) =
(z - 1)(z-3)2
centered at z = 3. Over what annulus in the complex plane is this series expansion
valid?
Transcribed Image Text:2) Find the Laurent series for 4z √(z) = (z - 1)(z-3)2 centered at z = 3. Over what annulus in the complex plane is this series expansion valid?
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