Find the first four nonzero terms in the Maclaurin series for cos²x-sinx. (Do not derive the series! Find this using existing series!)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem: Maclaurin Series Representation**

**Objective:** Find the first four nonzero terms in the Maclaurin series for \( \cos^2 x \cdot \sin x \).

**Instructions:** Do not derive the series from scratch; use existing series to find the terms.

### Explanation:

1. **Maclaurin Series Basics:**
   - A Maclaurin series is a type of Taylor series expansion about 0. It provides a way to express functions as infinite sums of terms calculated from the values of their derivatives at a single point.

2. **Existing Series:**
   - The Maclaurin series for \(\sin x\) is:
     \[
     \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots
     \]
   - The Maclaurin series for \(\cos x\) is:
     \[
     \cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots
     \]

3. **Approach:**
   - First, use the series for \(\cos x\) to find \(\cos^2 x\).
   - Multiply the expansion of \(\cos^2 x\) with the series for \(\sin x\).
   - Collect the first four nonzero terms.

By carefully applying these steps, you will obtain the required terms without deriving the series from scratch.
Transcribed Image Text:**Problem: Maclaurin Series Representation** **Objective:** Find the first four nonzero terms in the Maclaurin series for \( \cos^2 x \cdot \sin x \). **Instructions:** Do not derive the series from scratch; use existing series to find the terms. ### Explanation: 1. **Maclaurin Series Basics:** - A Maclaurin series is a type of Taylor series expansion about 0. It provides a way to express functions as infinite sums of terms calculated from the values of their derivatives at a single point. 2. **Existing Series:** - The Maclaurin series for \(\sin x\) is: \[ \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots \] - The Maclaurin series for \(\cos x\) is: \[ \cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots \] 3. **Approach:** - First, use the series for \(\cos x\) to find \(\cos^2 x\). - Multiply the expansion of \(\cos^2 x\) with the series for \(\sin x\). - Collect the first four nonzero terms. By carefully applying these steps, you will obtain the required terms without deriving the series from scratch.
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