2 equal charges, 149 micro Coulombs each, experiences an attraction force of 14 Newton. Calculate the distance between the charges in mm. Your Answer:
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Q: help
A: Approach to solving the question: Coulomb's lawDetailed explanation:
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- Two point charges, q, and q2 , are placed a distance d apart and exert a Coulomb force F on each other. If the distance between the charges is doubled, and q, is replaced with a charge 3q, ,what is the new Coulomb force between the charges?Point charges of 4.50 nC are situated at each of three corners of a square whose side is 0.150 m.A +30 nC charge is placed at a distance r = 5 mm from a +10 nC charge in free space. Calculate the magnitude of the force between the charges. Note: ε0=8.85x10-12 Fm-1
- Suppose you have a glass rod with a 0.68 μC charge and a polyester cloth with a -0.61μC charge, which are 13 cm apart. What is the magnitude of the attractive force between them (in N), using the approximation that they act like point charges? Numeric : A numeric value is expected and not an expression. | F | = ________Needs Complete typed solution with 100 % accuracy.1) A charge of 0.008 coulombs is placed at each corner of a square 100 meters on a side. The direction of the force on any of the four charges will be outward along the line passing through the center of the square and the charge being considered. What will be the magnitude of the force on each charge? (Express your answer without decimal places. Round your numbers.
- what is the force between two point charges that are 0.01 meters apart and each has a positive charge of 3 x 10^-6 Coulombs? The Coulomb constant k = 9x 10^9 N x m^2 / C^2An object has an excess charge of - 2.4 * 10 ^ - 1 C. How many excess electrons does it have?what is the force between two point charges that are 0.02 meters apart and each has a positive charge of 4x10^-6 coulombs? The coulomb constant k =9 x 10^9 N•m^2 /C^2