In the following equation using Coulomb's law: F = keq₁q₂/r² the final answer for force is negative. Why does this occur, it seems to pull the charge in a positive direction, to the right? Please select 2 answers below: 9.0x10^9 x (35 µC)(-43 µC)/(.043m)^2 = -7315 N a. In electrostatics the right direction is defined as (-). b. The (-) charge is simultaneously pulled to the left. c. Because it is a (-) charge that is pulling the (+) charge. d. There is an equal and opposite force. The force calculated is this opposite force, because of Newton's Third Law. e. The (-) from the equation means an attractive force, not a leftward force.
In the following equation using Coulomb's law: F = keq₁q₂/r² the final answer for force is negative. Why does this occur, it seems to pull the charge in a positive direction, to the right? Please select 2 answers below:
9.0x10^9 x (35 µC)(-43 µC)/(.043m)^2 = -7315 N
a. In electrostatics the right direction is defined as (-).
b. The (-) charge is simultaneously pulled to the left.
c. Because it is a (-) charge that is pulling the (+) charge.
d. There is an equal and opposite force. The force calculated is this opposite force, because of
e. The (-) from the equation means an attractive force, not a leftward force.
Given data
The electrostatic force is
The negative value of the electrostatic force implies that both the charge are of different signs. As per the given data, the first charge is positive in nature while the second charge is negative in nature.
From the above discussion, the charge is opposite and the nature of force is attractive.
So, option e is correct.
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