Two point charges, q, and q2 , are placed a distance d apart and exert a Coulomb force F on each other. If the distance between the charges is doubled, and q, is replaced with a charge 3q, ,what is the new Coulomb force between the charges?
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A: Given data: The force is F1=3 N And after increasing the distance a factor of 3
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Q: the force (in N)
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A: Given r = 1.5cm q1 = 2μC = 2×10-6 Cq2 = -4μC = -4×10-6 C
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A: Write the given values of this problem. Let, F1=2.50 NDiastance(r1)=rr2=5r
Q: What is the value of the mutual force between Two point charges, separated by 1.5 cm, having charge…
A: Given : d = 1.5 cm = 0.015 m q1 = 2 μC = 2 × 10-6 C q2 = -4 μC = -4 × 10-6 C ke = 8.99 × 109 Nm2/C2
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Q: Two charges, q1=-4.8mC and q2=--0.55mC are placed 5.23m apart from one another (mC stand for "milli-…
A: q1 = - 4.8mC q2 = 0.55 mC distance between the two charges (d) = 5.23 m
Q: Two point charges each experience a 3.12 N electrostatic force when they are 1.44 cm apart. What…
A: Given value--- Two point charges each experience a 3.12 N electrostatic force when they are 1.44 cm…
Q: Consider the point charges shown below. What will be the magnitude and direction of the force on the…
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- A +5 nC point charge and a -10 nC point charge are 0.02 m apart. (a) What is the strength of the Coulomb force on the +5 nC charge? (b) What is the strength of the Coulomb force on the -10 nC charge? (c) Is the -10 nC charge attracted to or repelled by the +5 nC charge (d) If the distance between the charges is doubled to 0.04 m, what is the force on the +5 nC charge now?Bead A has a mass of 15 g and a charge of -5.2 nC . Bead B has a mass of 22 g and a charge of -11.7 nC . The beads are held 15 cm apart (measured between their centers) and released.The force of repulsion between two identical positive charges is 0.800 N when the charges are 0.100 m apart. Find the value of each charge.
- Two charged spheres are separated by a distance R. The charges experience a force F. One of the spheres is then replaced with a new sphere that has twice the charge and is a distance of 0.5R away. What is the new force? Question 1 options: 4F 2F 8F FTwo point charges exert a 5.45 N force on each other. What will the force become if the distance between them is increased by a Factor of 6?Two charges, q1=-0.3mC and q2=--1.94mC are placed 12.02m apart from one another (mC stand for "milli-Coulomb"). What is the the electric force that q2 experiences due to the presence of q1? Note, if the force direction is "to the left" be sure to include a negative sign. If the direction of the force is "to the right", the force should be positive in sign.
- please help with questions 28,29,30I would like to have a factual solution and answer here please? thank you. Two point charges are placed on the x-axis as follows: Charge ?1 = +4.00 nC is located at ? = 0.200 m, and charge ?2 = +5.00 nC is at ? =−0.300 m. What are the magnitude and direction of the total force exerted by these two charges on a negative point charge Charge ?3 = −6.00 nC that is placed at the origin?