(2) Determine the areas under the normal curve given the mean of the distribution u = 80 and o = 5.5, andthe given value of the random variable x and the probability function in each item below. Write down theprobability function described in each and draw the normal curve with the proper shaded area of interest.1. The area of interest is bounded by the mean and x = 83.42.%3D2. The area of interest is bounded by the mean and x =

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Answered: (2) Determine the areas under the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Choose an American household at random and let the random variable ?X be the number of cars (including SUVs and light trucks) they own. Given is the probability distribution if we ignore the few households that own more than 5 cars. Number of cars 0 1 2 3 4 5 Probability 0.09 0.36 0.35 0.13 0.05 0.02 About what percentage of households have a number of cars within 2 standard deviations of the mean?
Subpart A,B,C
Suppose that the speed at which cars go on the freeway is normally distributed with mean 66 mph and standard deviation 5 miles per hour. Let X be the speed for a randomly selected car.a. What is the distribution of X? X ~ N( ________ , ________)b. If one car is randomly chosen, find the probability that it is traveling more than 62 mph. Round to 4 decumal places. c. If one of the cars is randomly chosen, find the probability that it is traveling between 68 and 71 mph. Round to 4 decimal places.
Subpart D,E,F
Four coins are tossed, and the number of heads is recorded. Shade the region on the histogram that gives the indicated probability. P(x > 2) Which of the following shaded regions gives the indicated probability? (Type A, B, C, or D.) A) 0.5- 0.38- 0.25- 0.13- 0- 0.5- 0.38 0.25- 0.13- लट 0 1 2 3 4 01 2 3 4 B) D) 0.5- 0.38- 0.25- 0.13- 0- 0.5- 0.38 0.25 0.13- 0- 0 1 2 3 4 0 1 2 3 4
pls answer no.9
accidents in two weeks? Q6- Assume the probability that a maple tree at age 5 grows less than 150 cm is equal to 0.3. If the height of maple trees at age 5 are estimated to be normally distributed with mean u cm and variance 64 cm. find u.
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 44 couples. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 44 births. The value of the mean is (Type an integer or a decimal. Do not round.) The value of the standard deviation is o = (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of girls or fewer are significantly low. (Round to one decimal place as needed.) Values of girls or greater are significantly high. (Round to one decimal place as needed.) c. Is the result of 35 girls a result that is significantly high? What does it…
Consider the population described by the probability distribution shown below. The random variable is observed twice with independent observations, as shown below. Complete parts a and b. Full data set X 3 4 5 6 p(x) 0.2 0.2 0.3 0.3 a. Complete the sampling distribution table. Type the medians in ascending order. Median 3 5 6 Probability || 0.08 0.24 (Simplify your answers. Type integers or decimals.) 4 0.18 (…) 0.04 Sample |3,3 3,4 3,5 Probability 0.04 0.06 Sample 5,3 5.4 Probability 0.06 0.06 3,6 4,3 0.06 0.04 4,4 4,5 4,6 0.04 0.06 0.06 5,5 5.6 6,3 6,4 0.09 0.09 0.06 0.06 6,5 6,6 0.09 0.09
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 30 couples. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 30 births. The value of the mean is u = (Type an integer or a decimal. Do not round.).
A sociologist randomly selects single adults for different groups of three, and the random variable x is the number in the group who say that the most fun way to flirt is in person. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied, P(x) O 0.086 0.326 0.414 0.174 Does the table show a probability distribution? Select all that apply. O A. Yes, the table shows a probability distribution. O B. No, the sum of all the probabilities is not equal to 1. O C. No, the random variable x's number values are not associated with probabilities. O D. No, the random variable x is categorical instead of numerical. O E. No, not every probability is between 0 and 1 inclusive.
Find the mean. variance, and standard deviation of the following probability distribution then interpret the computed values.

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