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2 Al(s) + 3 Cl2 (g) 2 AICI:(s) 2 Al(s) + 6 HCI(aq) → 2 AICI3(aq) + 3 H2 (g) AH = -1049 kJ/mole HС() — НСІ (aq) AH = -74.8 kJ/mole H2 (g) + Cl2(g) → 2 HCI (g) AH = -184.5 kJ/mole AICI3 (s) →AICI3 (aq) AH = -323 kJ/mole

2 Al(s) + 3 Cl2 (g) 2 AICI:(s) 2 Al(s) + 6 HCI(aq) → 2 AICI3(aq) + 3 H2 (g) AH = -1049 kJ/mole HС() — НСІ (aq) AH = -74.8 kJ/mole H2 (g) + Cl2(g) → 2 HCI (g) AH = -184.5 kJ/mole AICI3 (s) →AICI3 (aq) AH = -323 kJ/mole

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How do I, using Hess’s law and the data below, calculate the ∆H/mole for the reaction?
2 Al(s) + 3 Cl2 (g) 2 AICI:(s) 2 Al(s) + 6 HCI(aq) → 2 AICI3(aq) + 3 H2 (g) AH = -1049 kJ/mole HС(9) — НСІ (аq) AH = -74.8 kJ/mole H2 (g) + Cl2(g) –→ 2 HCI (g) AH = -184.5 kJ/mole AICI3 (s) →AICI3 (aq) AH = -323 kJ/mole
Transcribed Image Text:2 Al(s) + 3 Cl2 (g) 2 AICI:(s) 2 Al(s) + 6 HCI(aq) → 2 AICI3(aq) + 3 H2 (g) AH = -1049 kJ/mole HС(9) — НСІ (аq) AH = -74.8 kJ/mole H2 (g) + Cl2(g) –→ 2 HCI (g) AH = -184.5 kJ/mole AICI3 (s) →AICI3 (aq) AH = -323 kJ/mole
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