2) A trapezoidal channel lined with grass (n = 0.027) has a bottom width of 4.25 feet, side slopes of 2 horizontal to 1vertical, and a slope of 1.1 percent. Water is flowing at a depth of 2.35 feet. What is the discharge? Use ManningEquation and then check with the Manning's Charts. FIGURE A-3. (CHART 18) CHANNEL CHARTS FOR THE SOLUTION OF MANNING'S EQUATION.- 21.0-18.0-15.0-12.0-16.000:6-8.00002-100ウト-5.004.00DO'E-2.007.8009--1.2011.00-0.90-080-070-a.co-0.50-6.45-040-0.35DE D-0.25azaS10--0.1240.10POD2007F.P.S.VELOCITY38 38 3865P3n=.03DEPTH IN FEET7:215-18 8 6 5 VASCALESOUWAN8967U37 3335N5AT83MAXNCHART5SLOPE FEET PER FOOT10000018AVEN61-0723091&ba3602005€00500 06 09 04 77 29SDISCHARGE CUBIC FEET PER SECOND-QM15.012.010.0-9.00-8.00-7.00-10M5.00-4,003.00--0021.80.Fost0.60 21.20--0070.900.000.70--050045Fore0.35-DE'D0.25Fozo$100.12.0.100.08.-30'0QnCHANNEL CHART2:1b = 5 FT

Given data: B=4.25 fty=2.35 ftS=1.1100n=0.027Side slope 2:1 The discharge can be determined using…

2) A trapezoidal channel lined with grass (n = 0.027) has a bottom width of 4.25 feet, side slopes of 2 horizontal to 1 vertical, and a slope of 1.1 percent. Water is flowing at a depth of 2.35 feet. What is the discharge? Use Manning Equation and then check with the Manning's Charts.

2) A trapezoidal channel lined with grass (n = 0.027) has a bottom width of 4.25 feet, side slopes of 2 horizontal to 1 vertical, and a slope of 1.1 percent. Water is flowing at a depth of 2.35 feet. What is the discharge? Use Manning Equation and then check with the Manning's Charts.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Time and time related variables in engineering

Time is the event progression starting from past to present and then, future statistically. The time-related variable is any particular value in relation to time to assess its changes on a specified (XY) plane.

Question

2) A trapezoidal channel lined with grass (n = 0.027) has a bottom width of 4.25 feet, side slopes of 2 horizontal to 1
vertical, and a slope of 1.1 percent. Water is flowing at a depth of 2.35 feet. What is the discharge? Use Manning
Equation and then check with the Manning's Charts.

FIGURE A-3. (CHART 18) CHANNEL CHARTS FOR THE SOLUTION OF MANNING'S EQUATION.
- 21.0
-18.0
-15.0
-12.0
-16.0
00:6-
8.00
002-
100ウト
-5.00
4.00
DO'E
-2.00
7.80
09-
-1.20
11.00
-0.90
-080
-070
-a.co
-0.50
-6.45
-040
-0.35
DE D
-0.25
aza
S10-
-0.12
40.10
POD
2007
F.P.S.
VELOCITY
38 38 38
65
P
3
n=.03
DEPTH IN FEET
7:2
15-1
8 8 6 5 VASCALE
SOU
WAN
8967
U
37 3335
N
5
A
T
83
MAX
N
CHART
5
SLOPE FEET PER FOOT
100000
18
AVEN
6
1
-072
3091
&
ba
360
2005
€0050
0 06 09 04 77 29
S
DISCHARGE CUBIC FEET PER SECOND-Q
M
15.0
12.0
10.0-
9.00-
8.00-
7.00-
10
M
5.00-
4,00
3.00-
-002
1.80.
Fost
0.60 2
1.20-
-007
0.90
0.00
0.70-
-050
045
Fore
0.35-
DE'D
0.25
Fozo
$10
0.12.
0.10
0.08.
-30'0
Qn
CHANNEL CHART
2:1
b = 5 FT

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Can you please show how to do this problem? I’m confused on this homework question and please box answer and pleas write clear thank you.
A trapeziodal channel lined with grass (n = 0.027) has a bottom width of 4.25 feet, side slopes of 2 horizontal to 1 vertical, and a slope of 1.1 percent. Water is flowing at a depth of 2.35 feet. a) what is the discharge? b) what is the velocity?