2) A hin glass rod is a semicircle of radius R. as figure below, A charge is nonuniformly distributed along the rod with a linear charge density given by A=Ao sinocos0, where Ao is a positive constant. Point P is at the center of the semicircle. (a) Find the electric field Ē, (x and components) at point P. [Hint: you are intergrating from - y to + Do not assume Ex or Ey is zero, you have to intergrate.
2) A hin glass rod is a semicircle of radius R. as figure below, A charge is nonuniformly distributed along the rod with a linear charge density given by A=Ao sinocos0, where Ao is a positive constant. Point P is at the center of the semicircle. (a) Find the electric field Ē, (x and components) at point P. [Hint: you are intergrating from - y to + Do not assume Ex or Ey is zero, you have to intergrate.
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2) A thin glass rod is a semicircle of radius R. as figure below. A charge is nonuniformly distributed along the rod
with a linear charge density given by A=Ao sinOcos0, where Ao is a positive constant. Point P is at the center of
the semicircle. (a) Find the electric field E, (x and y components) at point P. [Hint: you are intergrating from -
- to +) Do not assume Ex or Ey is zero, you have to intergrate.
R.
P.
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