(=2 7. A solution of potassium permanganate was used to titrate a 15.00 mL aliquot of 0.1942 M H₂O2, and the endpoint was determined to be at 42.37 mL. What is the molarity of the potassium permanganate solution?
(=2 7. A solution of potassium permanganate was used to titrate a 15.00 mL aliquot of 0.1942 M H₂O2, and the endpoint was determined to be at 42.37 mL. What is the molarity of the potassium permanganate solution?
Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.20QAP
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Can someone help me with number 7 please ☺️?
![imple.
Civi=C₂V2
M.M of Tris
is 121.148
consumed 38.93 mL of titrant. Calculate the weight of tris in
93
C2 (10)=0.00978 M (38,93mL)
C2=0.09978 M (38.93ml)
10 mL
0.3884 M = weg of tris (1000
woft.
121.14g/mol (10)
= 0.3884 M X 121.14 g/mal x10mt
476.51
1000
2HCl + tris →→→→> tris - HCl₂ + H ₂0
1000
75
= 0.3884 M
= 0.47g
0.47 & X50ML
comL
23.59
2.359
7. A solution of potassium permanganate was used to titrate a 15.00 mL aliquot of 0.1942 M
H₂O2, and the endpoint was determined to be at 42.37 mL. What is the molarity of the
potassium permanganate solution?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb28a889-b85d-42af-92bf-6ae6f0de3415%2Ff4421b6b-6aa5-4a98-b06c-2ca0f6bd7e94%2Fzu8zib_processed.jpeg&w=3840&q=75)
Transcribed Image Text:imple.
Civi=C₂V2
M.M of Tris
is 121.148
consumed 38.93 mL of titrant. Calculate the weight of tris in
93
C2 (10)=0.00978 M (38,93mL)
C2=0.09978 M (38.93ml)
10 mL
0.3884 M = weg of tris (1000
woft.
121.14g/mol (10)
= 0.3884 M X 121.14 g/mal x10mt
476.51
1000
2HCl + tris →→→→> tris - HCl₂ + H ₂0
1000
75
= 0.3884 M
= 0.47g
0.47 & X50ML
comL
23.59
2.359
7. A solution of potassium permanganate was used to titrate a 15.00 mL aliquot of 0.1942 M
H₂O2, and the endpoint was determined to be at 42.37 mL. What is the molarity of the
potassium permanganate solution?
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