*2-20. Determine the reactions on the b SOLUTION Equations of Equilibrium. Referring to the FBD of the beam shown in Fig. a, N can be obtained directly by writing the moment equation of equilibrium about point B. (+ΣΜΒ = 0; 10(8.667) + B(6.50)+25(4.333) N₁(13) = 0 NA = 21.5 k + → ΣΕ = 0; Using this result to write the force equation of equilibrium along the x and y axis, B 10.19 k = 10.2 k Bx + 21.5(5) (10+13 +25) 13 13 12 15 Nlb84e (ΣΕ, = 0; By + 21.5 By = 24.46 k = 24.5 k Open with Google Docs 10k 13 12 5(13) - (10 +13 +25)( (1)(B)k=13k 2.167ft 4.333ft (a) 5(³/3) - 13, 12 (13) = 0 Bx = 0 12k+(2) (13) K-25 k. 5 ft B₂ Page 20 / 46 A 1 k/ft Ans. Ans. Ans. 4 ft + 10 k 4 ft 12 k 4 ft 3 k/ft

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Bars

In civil engineering, bars refer to steel reinforcement bars or rebars. These are structural members primarily used for reinforcement purposes in masonry works. A bar is characterized by its cross-sectional area, which is negligible compared to its length. Bars are usually manufactured by steel which is uniform throughout the length, or by meshing multiple steel wires. Other materials of the bar include carbon steel, glass fiber, carbon fiber, and basalt fiber. The reinforcing bars are coated with epoxy resins and other materials to enhance some of their properties including corrosion resistance.