*2-20. Determine the reactions on the b SOLUTION Equations of Equilibrium. Referring to the FBD of the beam shown in Fig. a, N can be obtained directly by writing the moment equation of equilibrium about point B. (+ΣΜΒ = 0; 10(8.667) + B(6.50)+25(4.333) N₁(13) = 0 NA = 21.5 k + → ΣΕ = 0; Using this result to write the force equation of equilibrium along the x and y axis, B 10.19 k = 10.2 k Bx + 21.5(5) (10+13 +25) 13 13 12 15 Nlb84e (ΣΕ, = 0; By + 21.5 By = 24.46 k = 24.5 k Open with Google Docs 10k 13 12 5(13) - (10 +13 +25)( (1)(B)k=13k 2.167ft 4.333ft (a) 5(³/3) - 13, 12 (13) = 0 Bx = 0 12k+(2) (13) K-25 k. 5 ft B₂ Page 20 / 46 A 1 k/ft Ans. Ans. Ans. 4 ft + 10 k 4 ft 12 k 4 ft 3 k/ft

*2-20. Determine the reactions on the b SOLUTION Equations of Equilibrium. Referring to the FBD of the beam shown in Fig. a, N can be obtained directly by writing the moment equation of equilibrium about point B. (+ΣΜΒ = 0; 10(8.667) + B(6.50)+25(4.333) N₁(13) = 0 NA = 21.5 k + → ΣΕ = 0; Using this result to write the force equation of equilibrium along the x and y axis, B 10.19 k = 10.2 k Bx + 21.5(5) (10+13 +25) 13 13 12 15 Nlb84e (ΣΕ, = 0; By + 21.5 By = 24.46 k = 24.5 k Open with Google Docs 10k 13 12 5(13) - (10 +13 +25)( (1)(B)k=13k 2.167ft 4.333ft (a) 5(³/3) - 13, 12 (13) = 0 Bx = 0 12k+(2) (13) K-25 k. 5 ft B₂ Page 20 / 46 A 1 k/ft Ans. Ans. Ans. 4 ft + 10 k 4 ft 12 k 4 ft 3 k/ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Bars

In civil engineering, bars refer to steel reinforcement bars or rebars. These are structural members primarily used for reinforcement purposes in masonry works. A bar is characterized by its cross-sectional area, which is negligible compared to its length. Bars are usually manufactured by steel which is uniform throughout the length, or by meshing multiple steel wires. Other materials of the bar include carbon steel, glass fiber, carbon fiber, and basalt fiber. The reinforcing bars are coated with epoxy resins and other materials to enhance some of their properties including corrosion resistance.

Question

In the moment equations for B, I was wondering why they were not using cosine and sine fractions (ex. x=5/13 and y=12/13). Why is it not 10(12/13)(8.667)+B(6.50)+25(12/13)(4.333)-Na(12/13)(13) as the moment equation?

*2-20. Determine the reactions on the b
SOLUTION
Equations of Equilibrium. Referring to the FBD of the beam
shown in Fig. a, N₁ can be obtained directly by writing the moment
equation of equilibrium about point B.
(+ΣΜΒ = 0; 10(8.667) + B(6.50)+25(4.333) N₁(13) = 0
NA = 21.5 k
+
→ ΣΕ, = 0;
B 10.19 k = 10.2 k
Using this result to write the force equation of equilibrium along
the x and y axis,
Bx + 21.5(5/3) (10+13 +25)
12
(ΣΕ, = 0; By + 21.5 5(13) - (10 +13 +25)(
(13)
By = 24.46 k = 24.5 k
1312
15
NA A 32:
Open with Google Docs
10k
13
(1)(B)k=13k
2-167ft 4.333ft
(a)
= 0
Bx
= 0
12k+ (2) (13) K-25 k.
5 ft
B₂
Page 20 / 46
A
1 k/ft
Ans.
Ans.
Ans.
4 ft
+
10 k
4 ft
12 k
4 ft
3 k/ft

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