Consider the frame shown in (Figure 1). Suppose that F₁ = 21 kN Figure 2 m D 1.5 m B 1.5 m < 1 of 1 0.3 m C E ▼ Part A Determine the x and y components of reaction at pin A using scalar notation. Express your answers using three significant figures separated by a comma. 15. ΑΣΦ 41 | vec Az. Ay = Submit Part B Dz. Dy = Submit Request Answer Determine the x and y components of reaction at pin D using scalar notation. Express your answers using three significant figures separated by a comma. IVE ΑΣΦ ↓↑ vec Provide Feedback ? Request Answer kN kN
Consider the frame shown in (Figure 1). Suppose that F₁ = 21 kN Figure 2 m D 1.5 m B 1.5 m < 1 of 1 0.3 m C E ▼ Part A Determine the x and y components of reaction at pin A using scalar notation. Express your answers using three significant figures separated by a comma. 15. ΑΣΦ 41 | vec Az. Ay = Submit Part B Dz. Dy = Submit Request Answer Determine the x and y components of reaction at pin D using scalar notation. Express your answers using three significant figures separated by a comma. IVE ΑΣΦ ↓↑ vec Provide Feedback ? Request Answer kN kN
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![**Frame Analysis Problem**
**Problem Statement:**
Consider the frame shown in the figure. Suppose that \( F_1 = 21 \, \text{kN} \).
**Figure Description:**
The diagram shows a frame structure with points labeled A, B, C, D, and E. The frame is on a coordinate plane with horizontal \( x \) and vertical \( y \) axes.
- The frame has a vertical segment from point A to D, 2 meters in height.
- There is a horizontal segment from point A to B of 1.5 meters in length.
- Another horizontal segment from point B to C, also 1.5 meters in length.
- From point C, a vertical segment connects to point E, 0.3 meters from C.
- A force \( F_1 \) of 21 kN is acting downward at point E.
**Tasks:**
**Part A:**
Determine the \( x \) and \( y \) components of the reaction at pin \( A \) using scalar notation.
- Enter your answers using three significant figures separated by a comma.
- Answer format: \( A_x, A_y = \) [values] kN
**Part B:**
Determine the \( x \) and \( y \) components of the reaction at pin \( D \) using scalar notation.
- Enter your answers using three significant figures separated by a comma.
- Answer format: \( D_x, D_y = \) [values] kN
For both parts, solutions should consider the equilibrium of forces and moments acting on the frame. Use appropriate static equilibrium equations: \(\sum F_x = 0\), \(\sum F_y = 0\), and \(\sum M = 0\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc77f544a-ee3e-4902-8958-66e53c68e4a2%2Fb4bb2e0b-609f-45d6-91b9-fe0cd5450721%2Fb674fqe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Frame Analysis Problem**
**Problem Statement:**
Consider the frame shown in the figure. Suppose that \( F_1 = 21 \, \text{kN} \).
**Figure Description:**
The diagram shows a frame structure with points labeled A, B, C, D, and E. The frame is on a coordinate plane with horizontal \( x \) and vertical \( y \) axes.
- The frame has a vertical segment from point A to D, 2 meters in height.
- There is a horizontal segment from point A to B of 1.5 meters in length.
- Another horizontal segment from point B to C, also 1.5 meters in length.
- From point C, a vertical segment connects to point E, 0.3 meters from C.
- A force \( F_1 \) of 21 kN is acting downward at point E.
**Tasks:**
**Part A:**
Determine the \( x \) and \( y \) components of the reaction at pin \( A \) using scalar notation.
- Enter your answers using three significant figures separated by a comma.
- Answer format: \( A_x, A_y = \) [values] kN
**Part B:**
Determine the \( x \) and \( y \) components of the reaction at pin \( D \) using scalar notation.
- Enter your answers using three significant figures separated by a comma.
- Answer format: \( D_x, D_y = \) [values] kN
For both parts, solutions should consider the equilibrium of forces and moments acting on the frame. Use appropriate static equilibrium equations: \(\sum F_x = 0\), \(\sum F_y = 0\), and \(\sum M = 0\).
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