In the frame shown below, P is equal to 208. What is the value of the Vertical direction reaction force component at C in N? (note: enter your numeric answer only. No need to enter units. Give your answer to two decimal places) and negative to the down direction.Vertical force component at C, Cy = ______ N**Diagram Explanation:**The diagram illustrates a structural frame with a horizontal and an inclined member:- **Points:** - A: The lower left point where the inclined member is supported. - B: The point where the inclined member connects to the horizontal member, 3 meters above point A. - C: The endpoint of the horizontal member where the vertical reaction force is measured. - P: A downward force located 2 meters from B along the horizontal member.- **Dimensions:** - The inclined member AB is at a 60° angle with the ground. - The horizontal member BC has a total length of 4 meters, split into two 2-meter sections from B to the point where force P acts, and then to point C.- **Force:** - A vertical force P acts downward at the midpoint of the horizontal member.

Answered: Image /qna-images/answer/951dce47-fe42-430a-8f05-b2cf7b90d910.jpg

In the frame shown below, P is equal to 208. what is the value of the Vertical direction reaction force component at C in N? (note: enter your numeric answer only. No need to enter units. Give your answer to two decimal places) and negative to the down direction. Vertical force component at C, Cy = 3 m 2 m m-

In the frame shown below, P is equal to 208. what is the value of the Vertical direction reaction force component at C in N? (note: enter your numeric answer only. No need to enter units. Give your answer to two decimal places) and negative to the down direction. Vertical force component at C, Cy = 3 m 2 m m-

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

2. The telescoping rod shown in Figure forces the pin P to move along the fixed path 9y=x² where x and y are in inches. At any time t, the x coordinate of P is given by x=t²-5t. Determine the y components of velocity and acceleration of P at x = 6in.
Determine the value of the force P that will prevent the cantilever beam from deflecting at the free end. EI is constant. Use the double integration method.
The continuous beam shown in the figure is fixed at both ends A and D, and supported by rollers at B and C. Assume I 800 x 106 mm and E = 70,000 MPa. %3D W1 BO C 8m 8 m 4 m 4 m W1 (kN/m) F (kN) s (mm) 20 60 25 If there is a settlement of S at the support C, solve the following using slope deflection method: 3. Reaction at A, RA in kN. 4. Moment at A, MA in kN-m 5. Reaction at D, RD in kN 6. Moment at D, MD in kN-m
For the forces acting on the beam shown in Figure 3.1a, determine the location of the equivalent resultant force with reference to point B in m. Given a = 1.5, b = 4.5, P1= 40 and w = 20. (Note: Prefix the answer with negative sign "" if the location is to the left of the reference point. E.g. if the location of the equivalent resultant force is located between points A and B, or to the left of point B by 1.2m, the answer should be "-1.2" with reference to point B) P, kN W kN/m A C a m b m
1 - Two circular bars are connected in series, as shown in the figure. An upward pressure of 50 MPa is applied on the exposed end surface of Bar 1. 5=120mm A downward load of 800 kN is applied at the end of Bar 2. Determine the displacements of points C and D under the applied loading. t=2000) -80mm P=240KN E₁=200 GPa E₂=75 GPa 50MPa 5=60mm Bar 1 B Bar 2 200 mm 80mm 200 mm 800 KN
Please explain this concept using a free body diagram. please be sure ,I will rate the solution.
In the system whose loading status is given in FIGURE 2, only bending effects are considered.with "Double Integration" method;a) Cross section rotation of the beam at B point (BB) in radian unit,b) Calculate the vertical displacement (yc) of the beam at point C in mm.Beam bending stiffness (EI) is constant along the rod and its value is 10000 tm2. t/m=5 a=2m b=5m
Question 6 Determine the moment at C for the beams shown using the three-moment equation. Express your answer in kip-ft and use two decimal places. 40 k 2.5 k/ft D – 24 ft – -12 ft+1 -24 ft E = constant
. In the figure shown below, compute the moment of inertia at the centroidal axis along x. A. Ix =1971in B, Ix =1791 in* C. Ix =648 in* D. Ix =684 in* В O D
9. Determine the resultant of the parallel force system acting on the bar AB shown in the figure below. The forces and positions are given in the figure. (Answer: R= 40 b. downward at 3.25 ft from point B or 4.75 from pt A) 20 lb 10lb H 3' 30th 40lb 10 Two unlike parallel forces of magnitude 400 N and 100 N are acting i way that
A smooth sphere of weight Wis supported by a string fastened to a point C on sphere and point A on the smooth vertical wall. The sphere is in contact with the wall at point B as shown in figure. If the length of the string AC is equal to the radius of sphere, then sum of magnitude of tension (T) in the string and reaction (R) on the wall is. W. (Round off two decimal places). A B Wall String Sphere Length of string AC = Radius
For the beam and loading shown, use discontinuity functions to compute (a) the slope of the beam at B and (b) the deflection of the beam at C. Assume a constant value of EI = 44 x 106 lb·ft2 for the beam; w0 = 6500 lb/ft, LAB = 4.5 ft, LBC = 10 ft, LCD = 5 ft.