1H-nmr signal at 4.2 (d) is due to *'H NMR Spectrumexchangeswith D;0(200 MHz. CDCI, solution)expansionExpansion7.06.2 ppm383.0 ppmTMS108764318 (ppm)OH-OCH2 aliphaticC-H AromaticCH3 aliphaticvinylic H

The NMR signal of -OH occurs at around 2-3 ppm. The aromatic C-H occurs in the range of around 7-8…

1H-nmr signal at 4.2 (d) is due to * "H NMR Spectrum 200 MHz. CDCI, solution) exchanges with D,0 expansion expansion 7.0 6.2 ppm 38 3.0 ppm TM 9 8 6 3 2 1 8 (pE OH -OCH2 aliphatic C-H Aromatic CH3 aliphatic vinylic H

1H-nmr signal at 4.2 (d) is due to * "H NMR Spectrum 200 MHz. CDCI, solution) exchanges with D,0 expansion expansion 7.0 6.2 ppm 38 3.0 ppm TM 9 8 6 3 2 1 8 (pE OH -OCH2 aliphatic C-H Aromatic CH3 aliphatic vinylic H

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

1H-nmr signal at 4.2 (d) is due to *
'H NMR Spectrum
exchanges
with D;0
(200 MHz. CDCI, solution)
expansion
Expansion
7.0
6.2 ppm
38
3.0 ppm
TMS
10
8
7
6
4
3
1
8 (ppm)
OH
-OCH2 aliphatic
C-H Aromatic
CH3 aliphatic
vinylic H

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