1)A sample of seven containers of fuel have a mean content of 10.0 liters with standard deviation of 0.283 liters. A 95% confidence interval for the mean content of all such containers (rounded off to two decimals) is: 2)In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that 160 preferred seafood. A 99% confidence interval for the actual proportion of people eating seafood on Fridays (rounded off to two decimals) is:

Q: Given the following measurements from a normal distribution: 8.6, 16.7, 18.5, 11.7, 9.7 a) Use the…

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Q: The data were collected in the men's 100-meter run of 16 secondary school students, and the mean…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: Six 3-year-old sheep were injected with an antibiotic. Their blood serum concentrations of…

A: Let X1, X2, ...., Xn be a random sample of size n from a population with mean and variance unknown.…

Q: f. A sample of 60 Grade 10 students' ages was obtained to estimate the mean of all Grade 9 students.…

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Q: A quality control manager wants to be sure that the standard deviation of oil containers is below a…

A: Let Xi be the amount of oil in the ith container,i=1,2,...,n.

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

A: Using Excel formula “=NORM.S.INV(1-(0.04/2))”, the critical value for 96% confidence level is…

Q: A sample of 100 homes in city A and 100 homes in City B was taken to estimate the proportion of the…

A: Given that, A sample of 100 homes in city A and 100 homes in city B were taken to estimate the…

Q: A sample of 200 found that 43.2% of those sampled consumed more than 2 alcoholic  beverages  a week.…

A: Given:

Q: the standard deviation of the 16 observations was 0.95 inches (again, the sample mean was 17.2).…

A: Given :  Standard deviation of the 16 observations was 0.95 inches & the sample mean was 17.2.…

Q: An experiment was designed to estimate the mean difference in weight gain for pigs fed ration A as…

A: Solution: A B d=A-B (d-d) (d-d)2 63 61 2 -3 9 57 52 5 0 0 64 54 10 5 25 51 45 6 1 1 45…

Q: In a survey, 45 people were asked how much they spent on their last partners birthday gift. The…

A: Given information- Sample size, n = 45 Significance level, α = 0.10 Sample mean, x-bar = $90 Sample…

Q: Noise levels in a hospital were measured at 81 different locations. The average level was found to…

A: It is given that, Sample mean = 61.2 decibels. Sample standard deviation, s is 7.9 decibels. The…

Q: A 95% confidence interval for the mean was computed with a sample of size 90 to be (16,22). a. What…

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Q: A local health centre noted that in a sample of 400 patients, 80 were referred ta hospital. a.…

A: Given, n = 400            x = 80 Therefore, population proportion p^ = 80400 = 0.2 The critical…

Q: Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11,12,15. There are…

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Q: The local Health Department conducted a study in 2009 of 900 adults asking each adult the number of…

A: Given Information: Sample size (n) = 900 Sample mean (x¯) = 7.946 Standard deviation = 6.567…

Q: A sample of 15 found that 43.2% of those sampled consumed more than 2 alcoholic  beverages  a week.…

A:

Q: the following sample was taken from a normally distributed population: 20,27,15,2016,22 and 13. A…

A:

Q: A sample of 50 employees is found to have a mean of $32474 and a standard deviation of $1334. A)…

A:

Q: Calculate a 95% upper confidence bound for the mean of a normally distributed population using the…

A: Given that, x = 32289  s = 2846  n=15  For 95% confidence interval,the z value is 1.96

Q: A sample of 50 students was taken from the local university. These students spent an average of R170…

A: Given information- Sample size (n) = 50 Mean x̅ = R170 Standard deviation (s) = R25.50 Significance…

Q: A fitness center is interested in finding a 98% confidence interval for the mean number of days per…

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Q: The mean IQ score of a sample of 61 students selected from a high school is 93. Suppose the standard…

A: Construct the 99% confidence interval for the population mean The 99% confidence interval for the…

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: Find a 95% confidence interval on the difference in mean life. Find the following: a. Pooled…

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Q: Six measurements were made of the concentration (in percent) of ash in a certain variety of spinach.…

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Q: Peter collects data on the music scores of 200 randomly selected concertos. The sample mean of this…

A: It is given that the mean is 85,252 and the standard deviation is 8,413.

Q: . A stationary shop would like to estimate the average retail value of greeting cards that it has in…

A: Sample size (n) =20 Sample mean (x-bar) = 167 Standard deviation (s) =32 The 95% confidence interval…

Q: Measurements of the length of a random sample of 200 rods made by a certain machine  during one week…

A: Givensample size(n)=200Mean(x)=0.824standard deviation(s)=0.042α=1-0.95=0.05α2=0.025degrees of…

Q: 3. The comprehensive strength of concrete is being tested by civil engineer. He tests 10 specimens…

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Q: Samples of two different models of cars were selected, and the actual speed for each car was…

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Q: We are interested in estimating the average amount spent per customer for lunch in a restaurant in…

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Q: If a 90% confidence interval for the mean is (75.3 to 80.9), we would reject H0:  =70 in favor of…

A: Given, 90% confidence interval (75.3,80.9) i.e. The hypothesis to be tested is given as:

Q: 1. The strength of a fiber is normally distributed with a known population standard deviation of 12…

A: Here since the population standard deviation is given we use the Z value for the computation of…

Q: A quality control expert at a pretzel factory took a random sample of 10 bags from a production run…

A:

Q: The bonus of the staff of the company is under the normal distribution. The bonuses of the 26…

A: The bonuses of the 26 employees are randomly selected and the following data were received: ∑ x =…

Q: To determine the views of students on a particular campus about fraternities, an 11-point attitude…

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Q: 2. A group of students working on their thesis took a random sample of 100 families in a certain…

A: Given Sample size=100, sample mean x̄=1146, sample standard deviations s=650  Construct 90% CI for…

Q: Samples of two different models of cars were selected, and the actual speed for each car was…

A:

Q: # 2 A sample of 64 airplanes gave a mean air time (time spent flying) of 49 hours. If the standard…

A: Given,population standard deviation(σ)=14.8sample mean(x¯)=49sample size(n)=64

Q: On the Stanford-Binet test, the mean IQ is 100. A class of 21 kindergarten pupils were tested with a…

A: Given  population mean μ=100, n=sample size=21, sample mean x̄=92, sample standard deviations s=6.92…

Q: In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta…

A: Variable:             A Variable is an attribute that describes the data like date, status, person,…