. A stationary shop would like to estimate the average retail value of greeting cards that it has in its inventory. A random sample of 20 greeting cards indicated an average value of Rs.167 and a standard deviation of Rs.32. Set up a 95% confidence interval estimate of all greeting cards that are in its inventory.
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. A stationary shop would like to estimate the average retail value of greeting cards that it has in its inventory. A random sample of 20 greeting cards indicated an average value of Rs.167 and a standard deviation of Rs.32. Set up a 95% confidence
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- Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 37 randomly selected people who train in groups, and finds that they run a mean of 47.7 miles per week. Assume that the population standard deviation for group runners is known to be 3.3 miles per week. She also interviews a random sample of 49 people who train on their own and finds that they run a mean of 49.4 miles per week. Assume that the population standard deviation for people who run by themselves is 4.4 miles per week. Test the claim at the 0.10 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.A researcher claims that the stomachs of blue crabs from Location A contain more fish than the stomachs of blue crabs from Location B. The stomach contents of a sample of 16 blue crabs from Location A contain a mean of 192 milligrams of fish and a standard deviation of 37 milligrams. The stomach contents of a sample of 11 blue crabs from Location B contain a mean of 189 milligrams of fish and a standard deviation of 45 milligrams. At α=0.01, can you support the researcher's claim? Assume the population variances are equal. Complete parts (a) through (d) below.The combined SAT scores for the students at a local high school are normally distributed with a mean of 1540 and a standard deviation of 299. The local college includes a minimum score of 2377 in its admission requirements. What percentage of students from this school earn scores that fail to satisfy the admission requirement? Give your answer as a percentage rounded to one decimal place.
- A prominent medical group claims that the population mean of the surgery durations for all brain tumor patients is 3.69 hours. You are a data analyst for a health insurance company and want to test that claim. To do so, you select a random sample of 32 brain tumor surgery patients, and you record the surgery duration for each. Assume it is known that the population standard deviation of the durations of all brain tumor surgeries is 1.68 hours. Based on your sample, follow the steps below to construct a 99% confidence interval for the population mean of the surgery durations for all brain tumor patients. Then state whether the confidence interval you construct contradicts the medical group's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results from your random sample of 32 brain tumor patients. (b) (c) Take Sample Sample size: Point estimate: Population standard deviation: Critical value: Compute 0.00 0.00 Number of patients Enter the values…Joan’s finishing time for the Bolder Boulder 10K race was 1.67 standard deviations faster than the women’s average for her age group. There were 415 women who ran in her age group. Assuming a normal distribution, how many women ran faster than Joan?Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
- A researcher claims that the stomachs of blue crabs from Location A contain more fish than the stomachs of blue crabs from Location B. The stomach contents of a sample of 14 blue crabs from Location A contain a mean of 194 milligrams of fish and a standard deviation of 37 milligrams. The stomach contents of a sample of 8 blue crabs from Location B contain a mean of 184 milligrams of fish and a standard deviation of 44 milligrams. At a = 0.05, can you support the researcher's claim? Assume the population variances are equal. Complete parts (a) through (d) below. (a) Identify the null and alternative hypotheses. Choose the correct answer below. ОА. Но H1-H2 0 OD. Ho: H₁-12₂=0 Ha H1 H₂0 enough evidence at the 5% level of significance to support the researcher's claim.Scientists collect a simple random sample of 25 menthol cigarettes and 25 non-menthol cigarettes. Both samples consist of cigarettes that are filtered, 100mm long, and non-light. The menthol cigarettes have a mean nicotine amount of 0.87 mg and a standard deviation of 0.24 mg. The non-menthol cigarettes have a mean nicotine amount of 0.92 mg and a standard deviation of 0.25 mg. Use a 0.05 significance level to test the claim that non-menthol cigarettes have greater amounts of nicotine than menthol cigarettes. Assume population variances are not equal.A random sample of 47 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $17.51 per car. The population standard deviation is $6.05. Estimate the mean bill for all cars from the drive thru with 91% confidence.
- A researcher claims that the stomachs of blue crabs from Location A contain more fish than the stomachs of blue crabs from Location B. The stomach contents of a sample of 13 blue crabs from Location A contain a mean of 191 milligrams of fish and a standard deviation of 37 milligrams. The stomach contents of a sample of 7 blue crabs from Location B contain a mean of 185 milligrams of fish and a standard deviation of 41 milligrams. At α=0.10, can you support the researcher's claim? Assume the population variances are equal and that both samples are from normal populations. Complete parts (a) through (d) below. (a) Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: μ1−μ2=0 Ha: μ1−μ2>0 B. H0: μ1−μ2<0 Ha: μ1−μ2=0 C. H0: μ1−μ2=0 Ha: μ1−μ2≠0 D. H0: μ1−μ2=0 Ha: μ1−μ2<0 (b) Calculate the test statistic t=? (Round to three decimal places as needed.) (c) Calculate the…The heights of 10 year old American children are normally distributed with a mean height of 4 feet and 5 inches (or 53 inches) and a standard deviation of 4.5 inches.In order to be allowed to go on a particular kids ride at the amusement park, children must be at least 44.9 inches tall and no more than 59.75 inches tall.What percent of 10 year old American children cannot go on the ride?A researcher claims that the stomachs of blue crabs from Location A contain more fish than the stomachs of blue crabs from Location B. The stomach contents of a sample of 13 blue crabs from Location A contain a mean of 191 milligrams of fish and a standard deviation of 38 milligrams. The stomach contents of a sample of 8 blue crabs from Location B contain a mean of 189 milligrams of fish and a standard deviation of 44 milligrams. At a = 0.10, can you support the researcher's claim? Assume the population variances are equal. Complete parts (a) through (d) below. t= 0.110 (Round to three decimal places as needed.) (c) Calculate the P-value. P=|| (Round to four decimal places as needed.)
