*19-40. A thin rod of mass m has an angular velocity w,while rotating on a smooth surface. Determine its newangular velocity just after its end strikes and hooks onto thepeg and the rod starts to rotate about Pwithout rebounding.Solve the problem (a) using the parameters given, (b)setting m = 2 kg, wn = 4 rad/s, I = 1.5 m.

(a) Given: The angular velocity of the rod = ω0 rad/s The mass of rod = m kg The length of rod = l…

Answered: *19-40. A thin rod of mass m has an…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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૨૩: If P = 200 N and the 15-kg uniform slender rod starts from rest at 0 = 0°, determine the rod's angular velocity at the instant just before 0 = 45°. Ans.: @₂ = 4.97 rad/s 45° 600 mm P = 200 N SOC
At the instant shown, the uniform slender rod with mass m = 31 kg is pin-supported at point O. It is subjected to a counterclockwise moment M = 68 N•m, has a counterclockwise angular velocity of W= 5.3 rad/s, and the dimensions a = 0.10 m and b = 0.65 m. Determine magnitude of the support reaction at point O at this instant. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper unit. Take g = 9.81 m/s2. a M
7-35. Block B of Fig. P 7-35 is constrained to move in a vertical slot. A is pinned to B and moves in the slot in member OE. The constant angular Block
Example: 18-63. The uniform 80-lb garage door is guided at its ends on the track. If it is released from rest at 0 = 0º, determine the door's angular velocity at the instant = 30°. The spring is originally stretched 1 ft when the door is held open, 0 = 0°. Assume the door can be treated as a thin plate, and there is a spring and pulley system on each of the two sides of the door. Solution: 8 ft A 8 ft B k = 9 lb/ft
19–33. The 80-kg man is holding two dumbbells while standing on a turntable of negligible mass, which turns freely about a vertical axis. When his arms are fully extended, the turntable is rotating with an angular velocity of 0.5 rev/s. Determine the angular velocity of the man when he retracts his arms to the position shown. When his arms are fully extended, approximate each arm as a uniform 6-kg rod having a length of 650 mm, and his body as a 68-kg solid cylinder of 400-mm diameter. With his arms in the retracted position, assume the man is an 80-kg solid cylinder of 450-mm diameter. Each dumbbell consists of two 5-kg spheres of negligible size. -0.20 m 0.65 m 0.3 m H0.3 m Prob. 19–33
At the instant shown, the spring is un-deformed. Determine the change in potential energy if the 20 kg disk (with radius of gyration kG = 0.5 m) rolls 2 revolutions without slipping. k= 200 N/m 3 m/s datum 0.3 m M = 2 Nm 30° O 1791 J O -1791 J O 1051 J O 1421 J O E) None of the above
A small object A is held against the vertical side of the rotating cylinderical container of raidus r due to entrifugal action the coefficient of astatic friction between the object and the container is , determine the expression for the maximum rotational rate co of the container which will keep the object from slipping out the vertical side. Fanpas (Fry: Mos FMS.N Fn-man +N=mrw +N=mYw² {fy.g +4₁ (norw')= ndg
?
Specifically a dynamics problem. Question in pic below.
The homogeneous cylinder A has a mass of 80 kg, and the mss of the hub can be neglected. The magnitude of the variable force P, is in newtons when t is in sec- onds. The velocity of body B changes from 2 m/s downward when t = 0 to 4 m/s downward t = 5 s. Determine the mass of B. Solve all questions using Impulse and Momentum methods
This is a dynamics question. Answer: w = 0.0906 rad/s

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