**19.26 (EX) Detecting genetically modified soybeans 1/2:**Most soybeans grown in the United States are genetically modified to, for example, resist pests and reduce the use of pesticides. Because some nations do not accept genetically modified (GM) foods, grain-handling facilities routinely test soybean shipments for the presence of GM beans. In a study of the accuracy of these tests, researchers submitted lots of soybeans containing 1% of GM beans to 23 randomly selected facilities. Eighteen detected the GM beans.**Explain why the conditions for the large-sample confidence interval are not met.**- The difference between the number of failures and number of successes is not large enough.- The sample size is too large.- The number of failures is smaller than 15.- We cannot be sure that the samples were chosen randomly. **19.26 (EX) Detecting genetically modified soybeans 2/2:**Provide a plus four 90% confidence interval for the percent of all grain-handling facilities that will correctly detect 1% of genetically modified (GM) beans in a shipment.Options:- ○ 0.7407 ± 0.1653- ○ 0.7407 ± 0.1387- ○ 0.7586 ± 0.1468- ○ 0.7407 ± 0.1080This is a question related to statistical inference, specifically confidence intervals. It presents four potential intervals based on the plus four method, a technique used to improve estimates of confidence intervals in certain statistical contexts.

Answered: Image /qna-images/answer/02e4b676-dc09-4c16-bf26-a9d81d7e37f9.jpg

Answered: 19.26 (EX) Detecting genetically…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a lake pollution study, the concentration of lead in the upper sedimentary layer of a lake bottom is measured from 25 sediment samples. The sample mean and the standard deviation of the measurements are found to be 0.38 and 0.06, respectively. Suppose Ho : u = 0.34 H1: u# 0.34 (a) State Type I and Type Il errors. (b) Conduct a hypothesis test at 0.01 level of significance by doing the seven-step classical approach. (please show all seven steps, formulas, calculations and the curve)
Test whether mu 1 less than mu 2μ1<μ2 at the alphaα=0.01 level of significance for the sample data shown in the accompanying table. Assume that the populations are normally distributed. Determine the null and alternative hypothesis for this test. A. H0:mu 1<mu 2μ1<μ2 H1:mu 1= mu 2μ1=μ2 B. Upper H 0 :H0:mu 1 equals mu 2μ1=μ2 Upper H 1 :H1:mu 1 not equals mu 2μ1≠μ2 C. Upper H 0 :H0:mu 1 not equals mu 2μ1≠μ2 Upper H 1 :H1:mu 1 less than mu 2μ1<μ2 D. Upper H 0 :H0:mu 1 equals mu 2μ1=μ2 Upper H 1 :H1:mu 1 less than mu 2μ1<μ2 Your answer is correct. Detemine the P-value for this hypothesis test. Pequals=nothing (Round to three decimal places as needed.)
A newly installed automatic gate system was being tested to see if the number of failures in 1,000 entry attempts was the same as the number of failures in 1,000 exit attempts. A random sample of eight delivery trucks was selected for data collection. Do these sample results show that there is a significant difference between entry and exit gate failures? Use α = 0.05. Truck 1 Truck 2 Truck 3 Truck 4 Truck 5 Truck 6 Truck 7 Truck 8 Entry failures 44 42 53 56 62 53 48 43 Exit failures 48 50 55 60 57 48 50 48 Click here for the Excel Data File (b) Find the test statistic tcalc. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) (c) Find the critical value tcrit for α = 0.05. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) (d) Find the p-value. (Round your answer to 4 decimal places.) (e) State your conclusion. Automated Gate: Number of…
Consider the following population model that satisfies the CNLRM assumptions: Y; = β2X; + ui in particular assume that: u ~ N (0,1) Win What is the mean and variance of 3₁ ? 2Σ o? σ' Ο Ε(βι)=0,6 = {" Ο Ε(βι)=0,6 – Σ Ε(βι)=1,6 = EX (βι) = 1,6% = ΣΧ Στ x σ βι n Ο Ο E ΣΧ ηΣ Cannot be determined with the information provided.
A newly installed automatic gate system was being tested to see if the number of failures in 1,000 entry attempts was the same as the number of failures in 1,000 exit attempts. A random sample of eight delivery trucks was selected for data collection. Do these sample results show that there is a significant difference between entry and exit gate failures? Use α = 0.05. Truck 1 Truck 2 Truck 3 Truck 4 Truck 5 Truck 6 Truck 7 Truck 8 Entry failures 40 42 53 55 62 54 50 42 Exit failures 47 52 56 56 60 46 52 45 (b) Find the test statistic tcalc. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) tcalc (c) Find the critical value tcrit for α = 0.05. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.) tcrit (d) Find the p-value. (Round your answer to 4 decimal places.) p-value
Refer to Exercise 8.S.6. Analyze these data using a Wilcoxon signed-rank test.
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,95110,951 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 184184 of their customers and calculates that these customers used an average of 11,162kWh11,162⁢kWh of electricity last year. Assuming that the population standard deviation is 1263kWh1263⁢kWh, is there sufficient evidence to support the power company's claim at the 0.050.05 level of significance? Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
carefully watched over a number of feedings. If it used its right paw more than half the time to activate the tube, it was defined to be “right-pawed." Observations of this sort showed that 67% of mice belonging to strain A/J are right-pawed. A similar protocol was followed on a sam- ple of thirty-five mice belonging to strain A/HeJ. Of those thirty-five, a total of eighteen were eventually classified as right-pawed. Test whether the proportion of right-pawed mice found in the A/HeJ sample was significantly differ- ent from what was known about the A/J strain. Use a two- sided alternative and let 0.05 be the probability associated with the critical region.
19.32 (EX) Side effects 1/6: An experiment on the side effects of pain relievers assigned arthritis patients to take one of several over-the-counter pain medications. Of the 440 patients who took one brand of pain reliever, 23 suffered some adverse symptom. If 10% of all patients suffer adverse symptoms, what would be the sampling distribution of the proportion with adverse symptoms in a sample of 440 patients? O Normal with mean 0.1 and standard deviation 0.0143. O Approximately Normal with mean 0.052 and standard deviation 0.0106. O Approximately Normal with mean 44 and standard deviation 6.293. O Approximately Normal with mean 0.1 and standard deviation 0.0143.
A newly installed automatic gate system was being tested to see if the number of failures in 1,000 entry attempts was the same as the number of failures in 1,000 exit attempts. A random sample of eight delivery trucks was selected for data collection. Do these sample results show that there is a significant difference between entry and exit gate failures? Use α = 0.05. Truck 1 Truck 2 Truck 3 Truck 4 Truck 5 Truck 6 Truck 7 Truck 8 Entry failures 44 42 53 56 62 53 48 43 Exit failures 48 50 55 60 57 48 50 48 Click here for the Excel Data File (a) Choose the appropriate hypotheses. Define the difference as Entry − Exit. multiple choice H0: μd = 0 versus H1: μd ≠ 0 H0: μd ≥ 0 versus H1: μd < 0 H0: μd ≤ 0 versus H1: μd > 0 Automated Gate: Number of Entry/Exit Failures Entry Exit In row format: Truck 1 44 48 Truck 1 Truck 2 Truck 3 Truck 4 Truck 5 Truck 6 Truck 7 Truck 8 Truck 2…
A report by the Gallup Poll found that a woman visits her doctor, on average, at most 5.8 times each year. A random sample of 20 women results in these yearly visit totals. Data: 4; 2; 1; 3; 7; 2; 9; 4; 6; 6; 7; 0; 5; 6; 4; 2; 1; 3; 4; 2 a. At the α = 0.05 level can it be concluded that the sample mean is higher than 5.8 visits per year? α = Ho: Ha: T – Test inpt: Data Stats µ0: List: Freq:1 µ ≠ µ0 < µ0 > µ0 Calculate T – Test µ0: t = p= sx : n: Decision: Compare the p-value with alpha and give your decision. Conclusion: b. Find a 95 % confidence interval of the true mean years visits of a woman to her doctor. TInterval Inpt: Data Stats sx : n: C-Level: . Calculate T-Interval ( , ) sx : n: Conclusion: We are 95% Confident……
A soft drink company has many bottling plants across the country. Based on its records, the company believes that an average of3. 4b6ttles out of a million break during the bottling process. Suppose that for an internal audit, the company selects40of its bottling plants and examines each one for evidence, at the significance level of0.10, that the number of broken bottles per million in the plant is significantly different fromµ=3. 4. That is, in each of the bottling plants, an independent hypothesis test is carried out, each with a null hypothesis.h and alternative hypothesish in the following way. ho: μ = 3.4.5 h₁: μ‡3.4.5 (to) For any one of the bottling plants, what is the probability that is rejected when in fact it is true? (b) Let's suppose is true for each of thebottling plants. For how many of the40bottling plants, on average, we would expecth is it rejected? 0 (c) Suppose again thath is true for each of the bottling plants. Would it be surprising thath will be rejected for4of…

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