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19. If K 0.45 at a (150°C) for the equilibrium reaction: N2 (g)+ O2 (g) ► 2NO The Ke of the reaction is : A) 0.45 B) 0.54 C) 0.69 D) 0.96. 20. If K (0.92) at a (150°C) for the equilibrium reaction: %3D CO(g) + 3H2(g) CH(g) + H2O(g) +→ The Ke of the reaction is : A) 1106.86 B) 2.32 x104 C) 4.20 x10S D) 3.29 x 105

19. If K 0.45 at a (150°C) for the equilibrium reaction: N2 (g)+ O2 (g) ► 2NO The Ke of the reaction is : A) 0.45 B) 0.54 C) 0.69 D) 0.96. 20. If K (0.92) at a (150°C) for the equilibrium reaction: %3D CO(g) + 3H2(g) CH(g) + H2O(g) +→ The Ke of the reaction is : A) 1106.86 B) 2.32 x104 C) 4.20 x10S D) 3.29 x 105

Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter17: Chemical Equilibrium
Section17.3: Using Equilibrium Constants
Problem 30SSC
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Solve 19 and 20 No steps needed Only choice
19. If K 0.45 at a (150°C) for the equilibrium reaction: %3D N2 (g)+ O2 (g) → 2NO The Ke of the reaction is : A) 0.45 B) 0.54 C) 0.69 D) 0.96. 20. If K (0.92) at a (150°C) for the equilibrium reaction: %3D CO(g)_+ 3H2(g) CH.(g) + H2O(g) The K. of the reaction is : Mww C) 4.20 x10S Ac Go A) 1106.86 B) 2.32 x104 D) 3.29 x 10$
Transcribed Image Text:19. If K 0.45 at a (150°C) for the equilibrium reaction: %3D N2 (g)+ O2 (g) → 2NO The Ke of the reaction is : A) 0.45 B) 0.54 C) 0.69 D) 0.96. 20. If K (0.92) at a (150°C) for the equilibrium reaction: %3D CO(g)_+ 3H2(g) CH.(g) + H2O(g) The K. of the reaction is : Mww C) 4.20 x10S Ac Go A) 1106.86 B) 2.32 x104 D) 3.29 x 10$
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