please help ### Question 19: Geometry Problem#### Instructions:DE is a midsegment of triangle ABC. Find the value of \( x \).#### Diagram:- The figure shows triangle ABC.- Points D and E are located on the sides AB and AC respectively, such that DE is parallel to BC and D is the midpoint of AB, and E is the midpoint of AC.- Segment DE is labeled with a length of 5 units.- The segment BC is labeled with a length of \( x \) units.#### Answer Choices:- 20- 15- 10- 5#### Detailed Solution:In the context of triangle ABC, since DE is a midsegment, it is parallel to BC and its length is half the length of BC. This means:\[ DE = \frac{1}{2}BC \]Given that the length of DE is 5 units, we can set up the equation:\[ 5 = \frac{1}{2}x \]To solve for \( x \):\[ 5 \times 2 = x \]\[ x = 10 \]#### Conclusion:The value of \( x \) is 10.#### Correct Answer:- 10

Name: please help ### Question 19: Geometry Problem#### Instructions:DE is a
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: please help ### Question 19: Geometry Problem#### Instructions:DE is a midsegment of triangle ABC. Find the value of \( x \).#### Diagram:- The figure shows triangle ABC.- Points D and E are located on the sides AB and AC respectively, such that DE i