19) Clausius-Clapeyron equation a) Consider the Clapeyron equation for a vaporization process. Since the molar volume of a gas is much larger than the molar volume of a liquid, the change in volume can be simplified by the gas volume. Using this information, derive the Clausius-Clapeyron equation from the Clapeyron equation under the assumption that the vapor behaves like an ideal gas and that Hap is constant over a small range. Hint: Use n = 1 mol and therefore the molar enthalpy of vaporization AH vap,molar. b) Use the Clausius-Clapeyron equation to determine the molar enthalpy of vaporization 4Hvap,molar of ethanol, given the following values for the vapor pressure: p₁ (349.05 K) = 0.93846 bar and p₂(350.75 K) = 0.99698 bar.

19) Clausius-Clapeyron equation a) Consider the Clapeyron equation for a vaporization process. Since the molar volume of a gas is much larger than the molar volume of a liquid, the change in volume can be simplified by the gas volume. Using this information, derive the Clausius-Clapeyron equation from the Clapeyron equation under the assumption that the vapor behaves like an ideal gas and that Hap is constant over a small range. Hint: Use n = 1 mol and therefore the molar enthalpy of vaporization AH vap,molar. b) Use the Clausius-Clapeyron equation to determine the molar enthalpy of vaporization 4Hvap,molar of ethanol, given the following values for the vapor pressure: p₁ (349.05 K) = 0.93846 bar and p₂(350.75 K) = 0.99698 bar.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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