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- Currently, studies are being done on whether one COVID vaccine (like Pfizer’s) can be mixed and matched with another COVID vaccine (like Moderna’s). So a person could have the first shot of one and the second shot of the other. Let’s say a study was done to try to determine if mixing and matching is as effective as just using one type for both shots. People show up at a clinic on a Saturday (self-selecting), and are first given the Pfizer vaccine, and then the Moderna vaccine 3 weeks later. Suppose the results showed that only 1% of all of the people got COVID. What is a problem with this study? A) There was no random assignment of participants to groups. B) It is observational, and an experiment would have been better due to the potential of confounding. C) There was no control group, i.e. a group to compare the results to. D) All of the aboveThe U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is registered to vote. Suppose that 679679 employed persons and 690690 unemployed persons are independently and randomly selected, and that 429429 of the employed persons and 369369 of the unemployed persons have registered to vote. Can we conclude that the percentage of employed workers ( p1p1 ), who have registered to vote, exceeds the percentage of unemployed workers ( p2p2 ), who have registered to vote? Use a significance level of α=0.05α=0.05 for the test. Step 2 of 6 : Find the values of the two sample proportions, pˆ1p^1 and pˆ2p^2. Round your answers to three decimal places.The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is registered to vote. Suppose that 713 employed persons and 613 unemployed persons are independently and randomly selected and that 338 of the employed persons and 244 of the unemployed persons have registered to vote. Can we conclude that the percentage of employed workers ( p1 ), who have registered to vote, exceeds the percentage of unemployed workers ( p2 ), who have registered to vote? Use a significance level of α=0.1 for the test. Step 1 of 6 : State the null and alternative hypotheses for the test. Step 2 of 6 : Find the values of the two sample proportions, pˆ1p^1 and pˆ2p^2. Round your answers to three decimal places. Step 3 of 6 : Compute the weighted estimate of p, p‾p‾. Round your answer to three decimal places. Step 4 of 6 : Compute the value of the test statistic. Round your answer to two decimal places.…
- Some researchers have conjectured that stem-pitting disease in peach tree seedlings might be controlled with weed and sol treatment. An experiment was conducted to compare peach tree seedling growth with sol and weeds treated with one of two herbicides. In a field containing 20 seedlings, 10 were randomly selected from throughout the field and assigned to receive Herbicide A The remaining 10 seedlings were to receive Herbicide B. Soil and weeds for each seedling were treated with the appropriate herbicide and at the end of the study period the height (in centimeters) was recorded for each seedling. A box plot of each data set showed no indication of non-Normality. The following results were obtained: x (cm) s (cm) Herbicide A 945 10 Herbicide B 109.1 A 95% confidence interval for ug - Ha is given by which of the following expressions? (Use the conservative value for degrees of freedom) (109 1-94 5) t1 96 (109 1-94 5) + 2 263 109 1- 94 5)2196, . (109 1- 945)2262, (109 1- 94 5)Where is the decision tree and how do I fold it back?Suppose that a magazinemagazine predicted that Candidate A would defeat Candidate B in a certain election. They conducted a poll of its subscribersits subscribers with a response rate of 2424%. On the basis of the results, the magazinemagazine predicted that Candidate A would win with 57% of the popular vote. However, Candidate B won the election with about 62% of the popular vote. At the time of this poll, most subscribers to the magazinesubscribers to the magazine belonged to the party of Candidate A. Name two biases that led to this incorrect prediction.Choose the correct answer below. A.Nonresponse bias: The low response rate caused bias.Response bias: The way the poll was administered showed bias. B.Sampling bias: Using an incorrect frame led to undercoverage.Nonresponse bias: The low response rate caused bias. C.Sampling bias: Using an incorrect frame led to undercoverage.Response bias: The way the poll was administered showed bias. Click to select your answer.
- Assume that when adults with smartphones are randomly selected 41% use them in meetings or classes. If 6 adult smartphone users are randomly selected, find the probabibility that at least 2 of them use their smartphones in meetings or classes.An executive board consists of a president (P) and three vice-presidents (V1,V2,V3)(V1,V2,V3). For a motion to pass it must have yes votes from three of the voting members, one of which must be the president's.A weighted system that could represent this situation is:[Q:P,V1,V2,V3][Q:P,V1,V2,V3]where:QQ = PP = V1V1 = V2V2 = V3V3 =QUESTION 4 For an unreplicated 29 factorial design in 8 blocks, QUESTIONE effects need to be selected to create the eight blocks and more effects will be automatically confounded within the blocks.
