18. Metal hydrides react with water to form hydrogen gas and the metal hydroxide such as in the reaction below. Calculate the percent yield of strontium hydroxide if 7.65g Sr(OH)2 was collected after reacting 9.30 g SrH2 with 3.24 g water. MW: SrH2 = 89.64g/mol, H2O = 18.02g/mol, Sr(OH)2= 121.63g/mol SrH2(s) + H2O) -> Sr(OH)2(s) + H2(g)

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Chapter3: Chemical Reactions
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18. Metal hydrides react with water to form hydrogen gas and the metal hydroxide such
as in the reaction below. Calculate the percent yield of strontium hydroxide if 7.65g
Sr(OH)2 was collected after reacting 9.30 g SrH2 with 3.24 g water.
MW: SrH2 = 89.64g/mol, H20 = 18.02g/mol, Sr(OH)2= 121.63g/mol
SrH2(s) + H2O) -> Sr(OH)2(s) + H2(9)
Transcribed Image Text:18. Metal hydrides react with water to form hydrogen gas and the metal hydroxide such as in the reaction below. Calculate the percent yield of strontium hydroxide if 7.65g Sr(OH)2 was collected after reacting 9.30 g SrH2 with 3.24 g water. MW: SrH2 = 89.64g/mol, H20 = 18.02g/mol, Sr(OH)2= 121.63g/mol SrH2(s) + H2O) -> Sr(OH)2(s) + H2(9)
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