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18. Metal hydrides react with water to form hydrogen gas and the metal hydroxide such as in the reaction below. Calculate the percent yield of strontium hydroxide if 7.65g Sr(OH)2 was collected after reacting 9.30 g SrH2 with 3.24 g water. MW: SrH2 = 89.64g/mol, H2O = 18.02g/mol, Sr(OH)2= 121.63g/mol SrH2(s) + H2O) -> Sr(OH)2(s) + H2(g)

18. Metal hydrides react with water to form hydrogen gas and the metal hydroxide such as in the reaction below. Calculate the percent yield of strontium hydroxide if 7.65g Sr(OH)2 was collected after reacting 9.30 g SrH2 with 3.24 g water. MW: SrH2 = 89.64g/mol, H2O = 18.02g/mol, Sr(OH)2= 121.63g/mol SrH2(s) + H2O) -> Sr(OH)2(s) + H2(g)

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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18. Metal hydrides react with water to form hydrogen gas and the metal hydroxide such as in the reaction below. Calculate the percent yield of strontium hydroxide if 7.65g Sr(OH)2 was collected after reacting 9.30 g SrH2 with 3.24 g water. MW: SrH2 = 89.64g/mol, H20 = 18.02g/mol, Sr(OH)2= 121.63g/mol SrH2(s) + H2O) -> Sr(OH)2(s) + H2(9)
Transcribed Image Text:18. Metal hydrides react with water to form hydrogen gas and the metal hydroxide such as in the reaction below. Calculate the percent yield of strontium hydroxide if 7.65g Sr(OH)2 was collected after reacting 9.30 g SrH2 with 3.24 g water. MW: SrH2 = 89.64g/mol, H20 = 18.02g/mol, Sr(OH)2= 121.63g/mol SrH2(s) + H2O) -> Sr(OH)2(s) + H2(9)
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