6- Question 6 of 17сMacmillan LearningSelect the compound with the higher boiling point.NF3NH3Select the compound with the higher boiling point.OCH₂CH₂CH₂CH₂CH₂CH₂Select the compound with the higher boiling point.CHACH₂F₂MacBook ProSearch or type URLHR MI

We have been given three questions related to intermolecular forces. Intermolecular forces can be defined as the forces between two or more than two molecules. Correct option is NH3. Explanation: Because in NH3, there is hydrogen bonding between hydrogen atom of one molecule of NH3 and highly electronegative atom , N of other NH3 molecule.But in NF3, there is no hydrogen bonding. Correct option is CH3CH2CH2CH3 Explanation: CH3CH2CH2CH3 is larger in size than CH3CH3, therefore magnitude of London dispersion forces is greater in CH3CH2CH2CH3.Thus more energy is needed to overcome these intermolecular forces in CH3CH2CH2CH3.Correct option is CH2F2. Explanation: Because dipole dipole forces in CH2F2 are stronger than London dispersion forces in CH4.Stronger the intermolecular forces, higher will be boiling point.

Answered: 17 Select the compound with the higher…

Science

Chemistry

17 Select the compound with the higher boiling point. ONF3 Ο NH,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

O (±)- (±)- (±)- -OME + (±)- ·}- H H. Il H- F HI H I H → ? LOMe H OMe
_H20(g) S03(g) +.
3. MF = CH10O CDCI3 240 QE-300 220 200 180 160 140 120 100 80 60 40 20 solvent 3. 2 12 11 10 9 6 4 1
Product?
ge.com/course.html?courseld=17842654&OpenVellumHMAC=d71eb8b5068468150149000 For each of the following acid-base reactions indicate whether it will favor reactants or products. Compound pK, CH3COOH 4.8 HCOOH 3.8 15.7 PO H₂O NH3 36 H₂O+ -1.7 CH3 O H₂ -2.5 PresentationO CH_NH,+HO- =CH,NH+H,O O products. reactants Submit ▾ Part B Request Answer NH3 + H₂O + NH4+ HO™ = reactants O products Submit Request Answer P Pearson Copyright © 2023 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy P
Draw the structural formula of the product of the reaction shown below. Please draw a clear and detailed image.
1-1. The raw water supply for a community contains 18 mg/L total particulate matter. It is to be treated by addition of 60 mg alum (Al2(SO4)3-14H;O) per liter of water treated. Essentially, all the added alum precipi- tates represented by the following reaction: Al2(SO4)3 · 14H20 → 2 Al(OH);(s) + 3So,- + 6H* + 8H2O For a total flow of 7500 m/d, compute the daily alum requirement, the total concentration of suspended sol- ids in the water following alum addition, and the daily load of particulate solids requiring disposal (including both those initially present and those formed during treatment).
3-6 3 SOLUTIONS AND NAME SOLUTION CONCENTRATIONS 1415 Section Pre-Lab Assignment Experiment objectives A, B, and C require you to devise procedures for preparing a saturated aqueous solution of potassium sulfate, experimentally determining the density of this solution, and experimentally determining the mass percent of potassium sulfate in this solution. Your pre-lab assignment is to develop procedures for parts A, B, and C. You will then execute these procedures in lab. PREPARATION OF A SATURATED AQUEOUS POTASSIUM SULFATE SOLUTION Reminder: use a maximum of 75 mL of water. A. В. DENSITY OF SATURATED AQUEOUS POTASSIUM SULFATE SOLUTION C. MASS PERCENT OF POTASSIUM SULFATE IN A SATURATED POTASSIUM SULFATE SOLUTION
For eac te, click the button under the better solvent. solute Which is the better solvent? :0: || :0: :0: CH,-S CH, НО -С — СH, — CH, — С — ОН CH;CH,OH CH; H C H
How many mL of solvent do you need to add to the amount gotten from the 2M Palmitic acid stock solution in order to prepare 250 mL total volume of your desired solution?
I need the answer as soon as possible
(4-10 only) A bottle of aromatic ammonia spirit has been recalled from the market for containing less amount of ammonia as compared with the content declared on its label. The label claims that it contains 2% v/v of ammonia. To confirm the legitimacy of this claim, an Assay testing must be conducted to quantify the amount of ammonia present in each bottles. The assay will involve reacting whatever amount of ammonia present in 10 mL sample with 30 mL of 0.25 M sulfuric acid for this reaction to occur: 2NH3 + H2SO4 → (NH4)2SO4 1. If the label claim of 2% v/v ammonia is true, how many moles of ammonia from a 10 mL sample will be available to react with sulfuric acid? The molar weight of ammonia is 17.031 g/mol. The density of ammonia is 0.73 g/mL. 0.0086 mol B. 0.0117 mol C. 0.0161 mol D. 0.1609 mol 2. Given the calculated moles of ammonia from the previous item, how many mL of 0.25 M Sulfuric acid is expected to react with it? 17.2 mL B. 22.2 mL C. 24.4 mL D. 26.8 mL 3. Therefore, of the…