16MB RAM sel Id cir Text Memory PC Value to Register A Bus B Bus C Bus 1 Rs, Rn 2 MUX Rs *3 MUX Rn MUX cip. cout MUX ALKO A D 7 16MB RAM ld cir str sel D

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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For the following diagram, match the numbers to the CPU unit it describes.

Group of answer choices

 

 

1
 

           [ Choose ]       

 Barrel Shifter           

  Rm             

Multiply Unit             

Immediate value            

 Shift Amount            

 ALU             

Memory         

 

2
   [ Choose ]       

 Barrel Shifter           

  Rm             

Multiply Unit             

Immediate value            

 Shift Amount            

 ALU             

Memory                

 

3
   [ Choose ]       

 Barrel Shifter           

  Rm             

Multiply Unit             

Immediate value            

 Shift Amount            

 ALU             

Memory         

 

4
   [ Choose ]       

 Barrel Shifter           

  Rm             

Multiply Unit             

Immediate value            

 Shift Amount            

 ALU             

Memory         

 

5
   [ Choose ]       

 Barrel Shifter           

  Rm             

Multiply Unit             

Immediate value            

 Shift Amount            

 ALU             

Memory              

 

6
   [ Choose ]       

 Barrel Shifter           

  Rm             

Multiply Unit             

Immediate value            

 Shift Amount            

 ALU             

Memory         

 

7
   [ Choose ]       

 Barrel Shifter           

  Rm             

Multiply Unit             

Immediate value            

 Shift Amount            

 ALU             

Memory               

This diagram represents a simplified architecture of a computer processing unit with memory components and buses for data transfer.

### Components Explained:

1. **PC (Program Counter):** 
   - It holds the address of the next instruction to be fetched from memory.

2. **Buses (A Bus, B Bus, C Bus):**
   - **A Bus:** Pathway for data from the PC to the multiplexer (MUX).
   - **B Bus:** Transfers data internally between components.
   - **C Bus:** Used for data output to various components.

3. **MUX (Multiplexer):** 
   - Used to select between different data sources. There are multiple MUXes numbered in the diagram:
     - **MUX 1:** Selects data source for processing.
     - **MUX 2-5:** These are positioned in various pathways to manage data flow effectively for operations and storage.
     - **MUX 6:** Controls data direction to and from memory.

4. **ALU (Arithmetic Logic Unit):** 
   - Performs arithmetic and logical operations. It receives data inputs from B Bus and Rs/Rn (registers), and outputs results.
   - ALU also outputs a carry out signal (Cout) if needed.

5. **Registers (Rs, Rn):** 
   - Temporary storage for data during processing. Can be loaded or sourced for operations.

6. **Memory:**
   - **16MB RAM (Text Memory):** 
     - Direct connection with the A Bus and utilizes control signals: sel (select), ld (load), clr (clear).
   - **Another 16MB RAM module:** 
     - Interacts similarly as the first RAM, with additional control signals for storing data.

### Connections and Data Flow:

- The program counter (PC) sends the next instruction address via the A Bus.
- Data flows through the MUXes for appropriate operations in the ALU.
- The ALU processes data and results are routed via the C Bus to necessary storage or further operations.
- Data can also be stored or retrieved from the 16MB RAMs based on control signals.
- Components receive values directly through various pathways and can manipulate data flow, performing read/write operations as required.

This architecture emphasizes data flow control via buses and multiplexers, facilitating instruction handling, arithmetic operations, and memory storage in a structured and efficient manner.
Transcribed Image Text:This diagram represents a simplified architecture of a computer processing unit with memory components and buses for data transfer. ### Components Explained: 1. **PC (Program Counter):** - It holds the address of the next instruction to be fetched from memory. 2. **Buses (A Bus, B Bus, C Bus):** - **A Bus:** Pathway for data from the PC to the multiplexer (MUX). - **B Bus:** Transfers data internally between components. - **C Bus:** Used for data output to various components. 3. **MUX (Multiplexer):** - Used to select between different data sources. There are multiple MUXes numbered in the diagram: - **MUX 1:** Selects data source for processing. - **MUX 2-5:** These are positioned in various pathways to manage data flow effectively for operations and storage. - **MUX 6:** Controls data direction to and from memory. 4. **ALU (Arithmetic Logic Unit):** - Performs arithmetic and logical operations. It receives data inputs from B Bus and Rs/Rn (registers), and outputs results. - ALU also outputs a carry out signal (Cout) if needed. 5. **Registers (Rs, Rn):** - Temporary storage for data during processing. Can be loaded or sourced for operations. 6. **Memory:** - **16MB RAM (Text Memory):** - Direct connection with the A Bus and utilizes control signals: sel (select), ld (load), clr (clear). - **Another 16MB RAM module:** - Interacts similarly as the first RAM, with additional control signals for storing data. ### Connections and Data Flow: - The program counter (PC) sends the next instruction address via the A Bus. - Data flows through the MUXes for appropriate operations in the ALU. - The ALU processes data and results are routed via the C Bus to necessary storage or further operations. - Data can also be stored or retrieved from the 16MB RAMs based on control signals. - Components receive values directly through various pathways and can manipulate data flow, performing read/write operations as required. This architecture emphasizes data flow control via buses and multiplexers, facilitating instruction handling, arithmetic operations, and memory storage in a structured and efficient manner.
Expert Solution
Step 1

MSCPU

The MSCPU, which implements the flexible operand, or Operand2, of the ARM CPU, is represented in the provided figure as an abstract perspective.

The multiplier as well as the barrel shifter, two new operational units that are incorporated to the CPU to do computation before the values are sent to the ALU, distinguish the MSCPU from the 3-Address Load and Store CPU. The Multiply and Accumulate (mla) instruction and the Operand2 can now be implemented by the CPU owing to these new units.

Additionally, Logisim was utilized to generate this abstract CPU instead of using a drawing programme because the complexity of the picture made it simpler to implement the CPU in a circuit simulation programme like Logisim than to attempt to draw it abstractly. There are some differences when uizling Logisim, including the inclusion of a multiplexer (mux) to choose among inputs. A mux might be thought of by the reader as a device that decides which of two or more inputs gets sent to the output. A mux on the B bus, for instance, which is the mux with the Rm and immed inputs in the top centre of the diagram, decides whether to send a register, Rm, or immediate value ahead.

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