16. An inertial frame of reference is one in which Newton's first law of motion holds.
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Q: 7. A 75 kg astronaut orbits the moon at a distance of 2.5 x 106 m from its center. (Mass of moon =…
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Q: 7. A 75 kg astronaut orbits the moon at a distance of 7.0 x 106 m from its center. (Mass of moon =…
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Q: Which of the following is not one of, nor a direct consequence of, Kepler's Laws?
A: According to question we need choose correct option.
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- An intergalactic spaceship arrives at a distant planet that rotates on its axis with a period of T = 31 hours. The mass of the planet is M = 2.1 • 1025 kg. The spaceship enters a circular orbit with an orbital period that is equal to the planet's period for the rotation about its axis, T. a. Enter an expression for the radius of the spaceship’s orbit. b. Calculate the orbital radius in meters.What must the separation be between a 8.6 kg particle and a 6.2 kg particle for their gravitational attraction to have a magnitude of 4.3 × 10-12 N? Number Enter your answer in accordance to the question statement Units Choose the answer from the menu in accordance to the question statement This answer has no units° (degrees)mkgsm/sm/s^2NJWN/mkg·m/s or N·sN/m^2 or Pakg/m^3gm/s^3timesTask 1: Gravitational Fields 1. A person with a mass of 60 kg is inside a rocket that is moving straight up, away from the earth's surface. The radius of the earth is 6.38 x 105 m and the mass of the earth is 5.98 x 1024 kg. a. Find the force of gravity acting on the person at an altitude of 300 000 m. b. Find the altitude that will cause the person's weight to drop to one-quarter of its value on the earth's surface. 2. Mass 1 is four times as large as mass 2. Both masses are at rest and are separated by 200 m. Where could you place a third mass, mass 3, if the net force on 3 must be zero?
- 28. Which best describes the gravitational force? a. linear function of distance b. an infinite-range force c. applicable only to our solar system d. sometimes repulsive1We will use differential equations to model the orbits and locations of Earth, Mars, and the spacecraft using Newton’s two laws mentioned above. Newton’s second law of motion in vector form is: F^→=ma^→ (1) where F^→ is the force vector in N (Newtons), and a^→ is the acceleration vector in m/s^2,and m is the mass in kg. Newton’s law of gravitation in vector form is: F^→=GMm/lr^→l*r^→/lr^→l where G=6.67x10^-11 m^3/s^2*kg is the universal gravitational constant, M is the mass of the larger object (the Sun), and is 2x10^30 kg, and m is the mass the smaller one (the planets or the spacecraft). The vector r^→ is the vector connecting the Sun to the orbiting objects. Step one ) The motion force in Equation(1), and the gravitational force in Equation(2) are equal. Equate the right hand sides of equations (1) and (2), and cancel the common factor on the left and right sides. Answer: f^→=ma^→ f=Gmm/lr^→l^2 a^→=Gmm/lr^→l^2 x r^→/lr^→l r^→=r^→/lr^→l * Gmm Could you please…
- I am lost on the step by step in step #2: can you please break them down. thanks! The acceleration due to gravity at altitude h is given by gh = GMR + h2= GM(R+3.30R)2= 1(4.30)2×GMR2= 118.49×9.8 m/s2= 0.530 m/s2 The acceleration of meteoroid due to earth's gravitation is equals to 0.530 m/s2A centrifuge spins with a frequency of 3.1 x 103 Hz. A particle in a test tube is positioned5.2 cm from the center of the centrifuge (Hint - ac = 4π2rf2 and rest you have to explain)a) Determine the acceleration of the particle at this position from Earths frame of referenceb) Why do you think centrifuges need such a high frequency?c) Why do you think medical research’s want to separate particles at all?An astronaut is doing a spacewalk on a long tether at 0.1 km away from the International Space Station (mass of 420,000 kg). His spacesuit includes a very sensitive gravitometer, which indicates the gravitational force acting on the astronaut and his spacesuit from the ISS is 7.0 E−7 N. What is the mass of the astronaut in his suit if G = 6.67 E−11 N*m2/kg2? 1. 150 kg 2. 200 kg 3. 250 kg 4. 300 kg
- 14. "Weighing the moon": Knowing the mass of the Earth, ME, Earth-Moon distance, R, and period of moon orbiting around the Barycenter is T. The mass of the Moon can be determined as 47n? R3 (А) Мм GT2 47?R3/2 (B) Мм GT2 4n?R3 (C) Мм – MẸ GT? 4n²R3 (D) MM = MẸ GT2The Earth is about 81 times more massive than the Moon.The Earth and the Moon apply gravitational forces to each other. The magnitude of the gravitational force acting on the Earth is the gravitational force acting on the Moon.a greater thanb) equal toc) less thand) not enough information to tellConvert 8.2 from g/cm3 to SI units.