16. A physics student rides a moped for 1 hour going 30 mph, then spends 1.5 hours not moving, and finally travels for another 2.0 hours going 30.0 mph. What is the student's average speed for the trip?
16. A physics student rides a moped for 1 hour going 30 mph, then spends 1.5 hours not moving, and finally travels for another 2.0 hours going 30.0 mph. What is the student's average speed for the trip?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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(Not honor class)
![Average Speed =
Overall Distance / Total Time
d/t
units = m/s
16. A physics student rides a moped for 1 hour going 30 mph, then spends 1.5 hours not
moving, and finally travels for another 2.0 hours going 30.0 mph. What is the student's
average speed for the trip?
Solving for
Speed
Equation
speed
= distance/time
Substitute (work) 30 +0 + (2) 30 =
1 + 1.5 + (2) 30 =
Answer with units
888
F3
DII
DD
F4
F5
F6
F7
F8
F9
F10
F11
%23
2$
&
*
2
7
Y
U
* 00
W/](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3daa2756-7752-43b8-9183-5ccc0bf0e014%2Fa4619f93-a044-462d-bf85-9c7ed3a30bcc%2Fticma7m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Average Speed =
Overall Distance / Total Time
d/t
units = m/s
16. A physics student rides a moped for 1 hour going 30 mph, then spends 1.5 hours not
moving, and finally travels for another 2.0 hours going 30.0 mph. What is the student's
average speed for the trip?
Solving for
Speed
Equation
speed
= distance/time
Substitute (work) 30 +0 + (2) 30 =
1 + 1.5 + (2) 30 =
Answer with units
888
F3
DII
DD
F4
F5
F6
F7
F8
F9
F10
F11
%23
2$
&
*
2
7
Y
U
* 00
W/
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