16 please step by step easy way to explain please must use provided formula sheet v?Circular motion: a =g= 9.8 m/s?;Weight: Fg- mg,;Pavr=At- ma;ce of a solid ball is gluuh the other end of thes 2.00 m. The rod'sinertia of the systemE - EE = U+KKinetic energy: K --mm v; Potential energy: U, = mgy24v?= o'r;a-a r;1 rev = 2n rad;a, =rv=o r;Rotational motion:0 = Do + at;e - Do t+20a = o - oK=T=rx F;T= rFsino;+R.)Er = la;Ipoint mass = mrmR21Iaisk=LyF - mRout1Ired(end)miIshell=3 mR?Inoop= mR?Irod(center) =mL?mR?%3DIpall ==12I- Icom + MD²dWP =dtwork: W=t 0;K-lo 2W =Pavr=At2Rolling:Vcom = RoK =2Iom VcomT= f,RF,max = HFnIncline: F mgsin0 F mgcos0Angular momentum:Lpoint mass =m rxvL= mrvsin 0;L=m (r.v, - r,v.)kL= IoLI = LrI, o1 =I 202m,x1 +m2x2miy1+m2y 2m1 +m2X com =y com =m1 +m21.16. A 2-kg box is released from rest from the top of a 5-m-high frictionless ramp. At the bottom of the ramp the box hasan elastic collision with an 8-kg box that is initially at rest. The 2-kg box bounces off the 8-kg box and goes back up theramp. To what height does the 2-kg block return up the ramp before coming to rest?A. 0.4 mB. 0.8 mС. 1.0 mD. 1.8 mЕ. 2.5 m

Name: 16 please step by step easy way to explain please must use provided fo
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: 16 please step by step easy way to explain please must use provided formula sheet v?Circular motion: a =g= 9.8 m/s?;Weight: Fg- mg,;Pavr=At- ma;ce of a solid ball is gluuh the other end of thes 2.00 m. The rod'sinertia of the systemE - EE = U+KKineti