College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
15 please by easy way to explain step by step and must use provide formula given answer is 75.1

Transcribed Image Text:Circular motion: ae -
R
E - ma;
Weight: F= mg, ;
g= 9.8 m/s';
Pavr =
At
Kinetic energy: K
m v;
Potential energy: Ug = mgy
E, - Er
E = U+K
Rotational motion:
1 rev = 2n rad;
v -o r;
= o'r;
a-a r;
a,-
0 = 0o + at;
e - Do t+
20a = o - m K=-lo ?
T-rFsino;
T=rx F;
ET = la;
Ipoint mass = mr?
Iaisk =
mR 2
Iplpe =
2+R.
2
Ihoop = mR?
1
Irod(center) = mL
Irod(end) =-mL
Iball=
nR?
Ihell =
dW
P =
dt
W
Pavr =
At
I= Icom + MD?
work: W=t0; K=-lo -
2.
W =
2
Rolling:
Vcom = Ro
K=
2 +
T= f,R
F,max = H,Fn
m Vcom
Incline: Fg mgsin0 Fg mgcos0
Angular momentum:
Lpoint mass = m rxv
L= mrvsin 0;
L=m (r.vy - ryVz)k
L= Io
L = Lt
I, 0 =I 202
m,x1 +m2x2
m1y1 +m2y 2
X com =
Y com =
m, +m2
m1 +m2
d. 745
e. 1630
15. A uniform 120 N beam is supported in a horizontal position by a pin (hinge) and cable. The
cable is at a 37.0-degree angle with the vertical., as shown in the figure. What is the tension in
the cable in N?
nt of inertia 2.0 kg m is
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