(9,00 Puanlar)16 - The strength coefficient and strain-hardening exponent of a certain test metal are 500 MPa and 0,25 respectively. Acylindrical specimen of the metal with starting diameter375 MPa determine the final diameter of the specimen.58 mm is stretched. If the average flow stress on the part is (7.00 Puanlar)24- An cast iron is made in a sand mold using a sand core that weighs 40 kg. Determine the buoyancy force in Newtonstending to lift the core during pouring (Density of cast iron p = 7.16 g/cm3, Sand density = 1.6 g/cm3)

Answered: Image /qna-images/answer/42bb6e3b-ed50-4a39-a9dd-28ae76870cd4.jpg

16- The strength coefficient and strain-hardening exponent of a certain test metal are 500 MPa and 0,25 respectively. A cylindrical specimen of the metal with starting diameter 58 mm is stretched. If the average flow stress on the part is 375 MPa determine the final diameter of the specimen.

16- The strength coefficient and strain-hardening exponent of a certain test metal are 500 MPa and 0,25 respectively. A cylindrical specimen of the metal with starting diameter 58 mm is stretched. If the average flow stress on the part is 375 MPa determine the final diameter of the specimen.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 147 kN. - Length of the specimen is 28 mm. - The yield strength is 75 kN/mm2. - The percentage of elongation is 49 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 16 kN, iv) Young's Modulus if the elongation is 1 mm at 16 kN and (v) Final diameter if the percentage of reduction in area is 22 Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm) Initial Cross-sectional Area (in mm2)
A ceramic part for a jet engine has a yield strength of 66,215 psi and a plane strain fracture toughness of 5000 psi (in) ¾. To be sure that the part does not fail, we plan to assure that the maximum applied stress is only one-third the yield strength. We use a nondestructive test that will detect any internal flaws greater than 0.05 in. Iong. Assuming that f = 1.2 , does our non- destructive test have the required sensitivity? Type 1 for yes and O for no.
Subject :- Mechanical engineering
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 151 kN. - Length of the specimen is 23 mm. - The yield strength is 79 kN/mm2. - The percentage of elongation is 45 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 17 kN, iv) Young's Modulus if the elongation is 2.4 mm at 17 kN and (v) Final diameter if the percentage of reduction in area is 24 %. THE QUESTION IS : FIND THE Final Diameter of the Specimen after Fracture (in mm)????
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 157 kN. - Length of the specimen is 23 mm. - The yield strength is 89 kN/mm2. - The percentage of elongation is 45 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 18 kN, iv) Young's Modulus if the elongation is 1.3 mm at 18 kN and (v) Final diameter if the percentage of reduction in area is 25 %. Solution: Initial Cross-sectional Area (in mm2) The Diameter of the Specimen (in mm) Final Length of the Specimen (in mm) Stress at the elastic load (in N/mm2) Young's Modulus of the Specimen (in N/mm2) Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm)
A copper specimen subjected to the Brinell Hardness Test using hardened steel ball indenter of diameter 12 mm and the indentation diameter 3.87 mm is measured using an optical magnifying lens with a ruler. Draw the Brinell Hardness Test setup neatly and determine the force applied on the specimen. Take Brinell Hardness Number for copper as 807. Calculate: 1-Surface Area of Indentation (in mm2) 2-Applied Force (in N)
When the true strain equals 0.14 and the true stress equals 355 MPa, the tensile test specimen starts to neck. Find the strength coefficient and the strain-hardening exponent in the flow curve equation without knowing any more about the test.
Engineering strain of a mild steel sample is recorded as 0.100%. The true strain is (A) 0.010% (C) 0.099% (B) 0.055% (D) 0.101%
TelkomSA E estion CALCULATIONS 4.1 Using the given pulley radius and the weight values, calculate the torque applied to the specimens. ← 4.2 Calculate the theoretical angle of twist. 4.3 Calculate the experimental angle of twist for the specimen by using the dial gauge readings and the lever distance to where the dial gauge makes contact. 4.4 Calculate the maximum torsional shear stress and compare the values to the shear stress limits of the material and discuss. 4.76% Rod - Experiment T mass. displacement cog 2009 300g 400g soog Torsion of a Diameter of pulley - 180, 4 mm Length of rad 304mm Diameter of rod at Centre Point - [6,7mm). Measure distance of lever - 19,52 mm Aluminum Solid rod. displacement mass 9,11 mm 9,23 mm 2,34 mm Q. 47 mm g s S8 mm 11:57 3 O
A mild steel tensile specimen of initial length 44 mm and initial diameter 6.4 mm is subjected to a tensile test and the following data are obtained. - Yield Strength as 88 MPa - Maximum Strength as 212 MPa - Fracture Strength as 152 MPa - Percentage of Elongation as 63 % - Percentage of Reduction in area as 39% Determine the Fracture load The Final length in mm = The Final area in mm2 =
tensile test uses a circular test specimen that has a gage length of 50 mm and diameter = 20 mm. During the test the specimen yields under a load of 100,000 N. The corresponding gage length = 50.5 mm. This is the 0.2% yield point. The maximum load of 180,000 N is reached at a gage length = 65 mm. Determine (a) yield strength, (b) modulus of elasticity, and (c) tensile strength. (d) If fracture occurs at a gage length of 73 mm, determine the ductility. i need clear ans by hand and solve very very fast in 20 min and thank you | DYBALA
The diagram shows a plot from an uniaxial test of an unknown metal. The uniaxial tensile test specimen had an original cross-sectional radius of 3.0 mm, an initial gauge length of 42 mm. At failure, the cross-sectional radius was 1.2 mm. Determine the yield strength of the unknown metal and the true stress at failure.