An object of height 3.2 cm is placed at 22 cm in front of a diverging lens of focal length, f = - 16 cm. Behind the diverging lens, there is a converging lens of focal length, f = 16 cm. The distance between the lenses is 4 cm. In the next few steps, you will find the location and size of the final image. Hint a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is cm. (Use the sign to indicate which side the image is on; positive sign d₂1 = means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is cm. (Use the sign to indicate which side the image is on.) d;2 = c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is h₂1 cm. (Use the sign to indicate whether the image is upright (positive) or = inverted (negative).) d. How large is the final image formed by the second converging lens? Final image height is h₂2 = cm. (Use the sign to indicate whether the image is upright or inverted.)
An object of height 3.2 cm is placed at 22 cm in front of a diverging lens of focal length, f = - 16 cm. Behind the diverging lens, there is a converging lens of focal length, f = 16 cm. The distance between the lenses is 4 cm. In the next few steps, you will find the location and size of the final image. Hint a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is cm. (Use the sign to indicate which side the image is on; positive sign d₂1 = means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is cm. (Use the sign to indicate which side the image is on.) d;2 = c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is h₂1 cm. (Use the sign to indicate whether the image is upright (positive) or = inverted (negative).) d. How large is the final image formed by the second converging lens? Final image height is h₂2 = cm. (Use the sign to indicate whether the image is upright or inverted.)
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Question
Transcribed Image Text:- 16 cm.
-
An object of height 3.2 cm is placed at 22 cm in front of a diverging lens of focal length, f =
Behind the diverging lens, there is a converging lens of focal length, f 16 cm. The distance between the
lenses is 4 cm. In the next few steps, you will find the location and size of the final image.
Hint
a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is
cm. (Use the sign to indicate which side the image is on; positive sign
dil
means image is on the side of outgoing rays, and negative sign means image is on the side opposite to
the outgoing rays.)
b. Where is the final image formed by the second converging lens? Image distance from second lens is
cm. (Use the sign to indicate which side the image is on.)
d₁2
=
c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is
cm. (Use the sign to indicate whether the image is upright (positive) or
hil
=
inverted (negative).)
=
d. How large is the final image formed by the second converging lens? Final image height is h;2
cm. (Use the sign to indicate whether the image is upright or inverted.)
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