I0: ADD R4 = R1 + RO;Il: SUB R9 = R3 -R4;12: ADD R4R5 + R6;%3D13: LDW R2MEM [R3 + 100];14: LDW R2 = MEM [R2 + 0];15: STW MEM [R4 + 100]16: AND R2 = R2 & R1;R1, Target;18: AND R9 = R9 & R1;R2;17: BEQ R9 ==Consider a pipeline with forwarding, hazard detection, and 1 delay slot for branches. Thepipeline is the typical 5-stage IF, ID, EX, MEM, WB MIPS design. For the above code,complete the pipeline diagram below (instructions on the left, cycles on top) for the code. Insertthe characters IF, ID, EX, MEM, WB for each instruction in the boxes. Assume that there twolevels of bypassing, that the second half of the decode stage performs a read of source registers,and that the first half of the write-back stage writes to the register file. Label all data stalls(Draw an X in the,box). Label all data forwards that the forwarding unit detects(arrow between the stages handing off the data and the stages receiving the data). What is thefinal execution time of the code?CyclesI#6 7 8103911 121314I01112131415161718

Find the total cycles of the given codes:- I0: ADD R4 = R1 + R0;I1: SUB R9 = R3 - R4;I2: ADD R4 = R5…

16: AND R2 = R2 & R13; %3D 17: BEQ R9 == R1, Target; 18: AND R9 = R9 & R1; Consider a pipeline with forwarding, hazard detection, and 1 delay slot pipeline is the typical 5-stage IF, ID, EX, MEM, WB MIPS design. F complete the pipeline diagram below (instructions on the left, cycles on top) the characters IF, ID, EX, MEM, WB for each instruction in the boxes. Ass !!

16: AND R2 = R2 & R13; %3D 17: BEQ R9 == R1, Target; 18: AND R9 = R9 & R1; Consider a pipeline with forwarding, hazard detection, and 1 delay slot pipeline is the typical 5-stage IF, ID, EX, MEM, WB MIPS design. F complete the pipeline diagram below (instructions on the left, cycles on top) the characters IF, ID, EX, MEM, WB for each instruction in the boxes. Ass !!

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Computer Science 2. If the pipeline speedup is 1.8 and the only stalls are due to branching and there are 5 pipeline stalls due to branching, what was the pipeline depth?
Consider the two designs D1 and D2 for a pipeline processor. D1 has 5 pipeline stages with execution time of 4 ns, 3 ns, 5ns, 3ns and 4 ns. While the design D2 has 8 pipeline stages each with 4ns execution time. The buffer delay for both designs is 1 ns. How much time can be reduced in using design D2 over design D1 for executing 100 instructions?
2. Find the value of x for the following SAP-2 code(Table 2), where the desired delay is 190 ms. Suppose, the clock frequency is 2 MHz. Find the SAP-2 instruction table in Appendix A. Label Mnemonics MVI A, 25H MVI C, x MOV B,C L1 L2 NOP DCR A NOP JNZ L2 DCR B JNZ L1 HLT Table 2
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Question 8: Show by drawing and compare between two pipelining cases that contain 4- stage pipeline (fetch, decode, execute and write) and three instructiong 1- a pipelining case with hazard condition. 2- a pipelining case without hazard condition.
Question 29 A PDA has only one transition from state p to state q and it is labeled by 1,X/YZ. Then (p,101,X$) ► NOTE: (p, 101, X$) means (current state, input data, stack data). Input data is read one symbol at a time. O (9,01,ZY$) O (9,1101,ZY$) O (9,10,ZY$) O (9,01,YZ$) O (9,10,YZ$)
Assume a classical RISC pipeline with regular (not delayed) branches. This pipeline has five stages: Instruction Fetch (IF), Instruction Decode (ID), Execute Instruction (EX), Memory Access (MEM), and Writeback (WB). You may assume that there are no resource hazards in this pipeline, but data hazards may exist. Draw a timing diagram that shows the execution of the following instructions in this pipeline. Assume that R1, R2, etc. are registers while A, B, etc. are memory operands. The first operand is the destination while the second operand is the source. The numbers on the left are the addresses of the instructions. BRA is an unconditional branch to a target address 120.
Given three instructions below: Sub $2, $1, $3And $12, $4, $5Or $13, $6, $2 Modify the pipeline machine below (by adding the forwarding related lines and components) so that it can resolve the above data hazard of the third instruction (or $13, $6, $2). Please note that your modification should be just enough to resolve the given data hazard. Any additional modification (i.e., it does not involve the above data hazard) will result in a penalty. show your in-between work or explanation.
(A) Show with graph how we add the following floating point: X-0.541 x10', Y-0.947x10. Using Add operation to solve these floating points by using pipeline structure (X= 0.7100 x 10) and (Y = 0.1234 x 10) then draw the suitable circuit of this operation.
Determine the missing instruction from line 1 to 10
Pipelining with 1-stage Bypass Circuitry: Show the execution of the following sequence of MIPS instructions on a pipeline chart. Also show how source operands of ALUS are gathered for 12, 13, and 14 (i.e. read from the Register File at the Decode stage or forwarded from the first stage of the bypass circuitry) 11: LOAD R1, R8, #100 12: LOAD R2, R8, #500 13: ADD R3, R1, R2 14: STORE R3, R8, #1000