150 mm Weld thickness 6 mm Vdw = wtfyw/(√3 × Ymw) W
Te - Effective throat thickness well in mm = 6 sin45°
|
Consider the following drawing in which plate 1 is welded onto plate 2 as shown for tensile and shear loading. The plates are fillet welded with a weld thickness of 6 mm as shown for a length of 150 mm.
The plates have an ultimate strength of 275 MPa and the welding was done with F70 welding electrodes, which possesses an ultimate strength of 483 MPa.
Consider a partial factor of safety of 1.7 for the welded joint and determine the design strength of the weld joint, both in tension (Tdw) and in shear (Vdw) due to the forces acting on it.
a) Determine the design strength of the following weld in tension ( ) due to vertical forces. b) Determine the design strength of the weld in shear ( ) due to horizontal forces. |
Attached pic is shear equation for calculation
Tension equation for calculation is: Tdw = FyLwte /Ymw
Step by step
Solved in 1 steps with 2 images
