15. A particle is subject to a force F, that varies with posi- W tion as shown in Figure P7.15. Find the work done by the force on the particle as it moves (a) from x = 0 to x = 5.00 m, (b) from x= 5.00 m to x = 10.0 m, and (c) from x 10.0 m to x = 15.0 m. (d) What is the total work done by the force over the distance x = 0 to x = 15.0 m? = F, (N) 33 2 1 0 468 8 10 12 14 16 071 x (m)
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- A 0.42 kg particle has a speed of 5.0 m/s at point A and kinetic energy of 7.5 J at point B. (a) What is its kinetic energy at A? (b) What is its speed at point B? lea ng m/s (c) What is the total work done on the particle as it moves from A to B? Need Help? Read It ds.do on the shopping cart? W -107.5 J 2. You apply a force of 1.5 N at an angle of 34° from the vertical on a block that is sitting on a friction-less table. The force you apply causes the block to slide across the table for 1 m. How much work did you do to move the block? 0.84 J 3. An 8.5 kg package in a mail sorting room slides 20 mdown a chute thatWfric Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 100.0 kg down a 60° slope at constant speed, as shown in the figure. The coefficient of friction between the sled and the snow is 0.100. = (a) How much work is done by friction as the sled moves 30.0 m along the hill. Enter to 3 significant figures Wrope 1.47 × 10³ J = W grav 60° (b) How much work is done by the rope on the sled in this distance? Hint: use Newton's second law to find the tension. Enter to 3 significant figures W -2.39x104 T = 2.55×104 J (c) What is the work done by the gravitational force on the sled? Enter to 3 significant figures
- A can of sardines is made to move along an x axis from x = 0.44 m to x = 1.49 m by a force with a magnitude given by F = e-6x, with x in meters and F in Newtons. How much work is done on the %3D can by the force?d amolg 2. A 100 Newton force is applied to a 15kg box in the horizontal direction and moves it : meters horizontally. How much work was done? ps ow DI Amaapaid DI 3. There is a 2kg book lying on a table. A 64 N force is applied to the book at a 120° angle from horizontal and moves the book 3 meters in the horizontal direction. How much work was done?Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 85.0 kg down a 60° slope at constant speed, as shown in the figure. The coefficient of friction between the sled and the snow is 0.100. (a) How much work is done by friction as the sled moves 30.0 m along the hill. Enter to 3 significant figures W fric (b) How much work is done by the rope on the sled in this distance? Hint: use Newton's second law to find the tension. Enter to 3 significant figures Wrope W. grav 60° J (c) What is the work done by the gravitational force on the sled? Enter to 3 significant figures J W₁ W J (d) What is the work done by the normal force? WN= J total (e) What is the total work done? Enter to 3 significant figures Note: When adding work done by individual forces, DO NOT ROUND THE VALUES TO FIND THE SUM. J Sense-making: If the speed of the rescue sled & the victim is constant, what do you expect the total work done on the rescue sled and the victim to be? Does your answer support…