Two football players are in a competition to see who can pull a 150.0 kg container over the entire football field (100 yards) faster. One player pulls on a rope attached to the container at a 25o angle with a force of 125 N. The other player pulls on a rope directly aligned with the plane of the field (positive x-direction) with a force of 111 N. Which player will exert more work? Which player wins the race? Assume the football field is frictionless (thank goodness it actually isn’t). Hint: First, label all your forces and separate them all into x- and y-components.

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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  1. Two football players are in a competition to see who can pull a 150.0 kg container over the entire football field (100 yards) faster. One player pulls on a rope attached to the container at a 25o angle with a force of 125 N. The other player pulls on a rope directly aligned with the plane of the field (positive x-direction) with a force of 111 N. Which player will exert more work? Which player wins the race? Assume the football field is frictionless (thank goodness it actually isn’t). Hint: First, label all your forces and separate them all into x- and y-components.

Expert Solution
Step 1

Introduction:

According to Newton's 1st law of motion, at equilibrium, total force acting on the body is zero. Identification of different forces acting on the body can be given by free body diagram. With the help of free body diagram direction of different forces can be identified. 

Work done is the scalar quantity. It is the dot product of force and displacement. Work one by the body is depends on the orientation of the applied force.

Given data:

Mass of the container is,

m= 150 kg

Distance of football field is,

d= 100 yard= 91.44 m

One player pulls the container with angle made with horizontal.

θ1=250

F1= 125 N

Another player pulls the container with angle made with horizontal is,

θ2=00

F2= 111 N

Formula used:

Work done by the body is, 

W=F. dW=F. dcosθ

Where, 

F- Applied force

d- Displacement of the object

θ- Angle between F and d

According to work- energy theorem, 

Work done= Change in kinetic energy

W= Kf- KiW= 12mvf2- 12mvi2

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