Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 85.0 kg down a 60°slope at constant speed, as shown in the figure. The coefficient of friction between the sled and thesnow is 0.100.(a) How much work is done by friction as the sled moves 30.0 m along the hill.Enter to 3 significant figuresW fric(b) How much work is done by the rope on the sled in this distance? Hint: use Newton's second law tofind the tension.Enter to 3 significant figuresWropeW.grav60°J(c) What is the work done by the gravitational force on the sled?Enter to 3 significant figuresJW₁WJ(d) What is the work done by the normal force?WN=Jtotal(e) What is the total work done?Enter to 3 significant figuresNote: When adding work done by individual forces, DO NOT ROUND THE VALUES TO FIND THESUM.JSense-making: If the speed of the rescue sled & the victim is constant, what do you expect thetotal work done on the rescue sled and the victim to be? Does your answer support theprediction?

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Description: Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 85.0 kg down a 60°slope at constant speed, as shown in the figure. The coefficient of friction between the sled and thesnow is 0.100.(a) How much work is done by friction

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Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 85.0 kg down a 60° lope at constant speed, as shown in the figure. The coefficient of friction between the sled and the now is 0.100. = a) How much work is done by friction as the sled moves 30.0 m along the hill. Enter to 3 significant figures W fric Wrope b) How much work is done by the rope on the sled in this distance? Hint: use Newton's second law to ind the tension. Enter to 3 significant figures = W grav J 60° = W J c) What is the work done by the gravitational force on the sled? Enter to 3 significant figures J

Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 85.0 kg down a 60° lope at constant speed, as shown in the figure. The coefficient of friction between the sled and the now is 0.100. = a) How much work is done by friction as the sled moves 30.0 m along the hill. Enter to 3 significant figures W fric Wrope b) How much work is done by the rope on the sled in this distance? Hint: use Newton's second law to ind the tension. Enter to 3 significant figures = W grav J 60° = W J c) What is the work done by the gravitational force on the sled? Enter to 3 significant figures J

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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