15° T₁ W T₂ J.10° A 69-kg person is being pulled away from a burning building as shown in the figure above. Using the two equations found using Newton's Second Law in Part 2, compute the numeric values of the tensions T₁ and T₂. T₁= N T₂= N Hint: You will have to solve a system of linear equations to compute the tensions.

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The image contains two equations representing the equilibrium conditions of forces in a system.

1. **ΣFₓ = T₁ cos(105°) + T₂ cos(10°) = 0**  
   - This equation represents the sum of the horizontal components of forces in the x-direction. The forces T₁ and T₂ are resolved into their x-components using the cosine of their respective angles (105° and 10°). The sum of these components is set to zero, indicating equilibrium in the horizontal direction.

2. **ΣFᵧ = T₁ sin(105°) + T₂ sin(10°) - mg = 0**  
   - This equation represents the sum of the vertical components of forces in the y-direction. The forces T₁ and T₂ are resolved into their y-components using the sine of their respective angles (105° and 10°). The gravitational force (mg) is subtracted from the sum of these components, and the total is set to zero, indicating equilibrium in the vertical direction.
Transcribed Image Text:The image contains two equations representing the equilibrium conditions of forces in a system. 1. **ΣFₓ = T₁ cos(105°) + T₂ cos(10°) = 0** - This equation represents the sum of the horizontal components of forces in the x-direction. The forces T₁ and T₂ are resolved into their x-components using the cosine of their respective angles (105° and 10°). The sum of these components is set to zero, indicating equilibrium in the horizontal direction. 2. **ΣFᵧ = T₁ sin(105°) + T₂ sin(10°) - mg = 0** - This equation represents the sum of the vertical components of forces in the y-direction. The forces T₁ and T₂ are resolved into their y-components using the sine of their respective angles (105° and 10°). The gravitational force (mg) is subtracted from the sum of these components, and the total is set to zero, indicating equilibrium in the vertical direction.
**Problem 1: Rescue Scenario Analysis**

A diagram shows a 69-kg person being rescued from a burning building. The person is being pulled by a firefighter using a rope at an angle. The figure includes the following elements:

- The person is hanging vertically down with a weight force labeled as \( w \).
- Two tensions, \( T_1 \) and \( T_2 \), are exerted through ropes from different angles:
  - \( T_1 \) is at an angle of 15° from the vertical.
  - \( T_2 \) is at an angle of 10° from the horizontal, as the firefighter pulls at the person.

**Task:**
Using the two equations derived from Newton's Second Law in Part 2, calculate the numeric values of the tensions \( T_1 \) and \( T_2 \).

**Input Fields:**
- \( T_1 = \) [Input Box] N
- \( T_2 = \) [Input Box] N

**Hint:**
To find the tensions, you need to solve a system of linear equations.
Transcribed Image Text:**Problem 1: Rescue Scenario Analysis** A diagram shows a 69-kg person being rescued from a burning building. The person is being pulled by a firefighter using a rope at an angle. The figure includes the following elements: - The person is hanging vertically down with a weight force labeled as \( w \). - Two tensions, \( T_1 \) and \( T_2 \), are exerted through ropes from different angles: - \( T_1 \) is at an angle of 15° from the vertical. - \( T_2 \) is at an angle of 10° from the horizontal, as the firefighter pulls at the person. **Task:** Using the two equations derived from Newton's Second Law in Part 2, calculate the numeric values of the tensions \( T_1 \) and \( T_2 \). **Input Fields:** - \( T_1 = \) [Input Box] N - \( T_2 = \) [Input Box] N **Hint:** To find the tensions, you need to solve a system of linear equations.
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