: 14:36. The average test marks in a particular class is 79. The standard deviation is 5. If the marks áre distributed normally, how many students in a class of 200 did not receive marks between 75 and 82? Given: Pr {0
Q: (a) Find the z-score for an IQ of 86, rounded to three decimal places. (b) Find the probability…
A: mean = 100 s = 15
Q: Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. P(-b <…
A: Given information- We have given the z-scores are normally distributed with a mean of 0 and a…
Q: Suppose that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally…
A: Given information- Population mean, µ = 3.3 units/mL We have given that exactly 98% of healthy…
Q: IQ s normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual…
A: GivenMean(μ)=100standard deviation(σ)=15
Q: The mean yearly rainfall in Sydney, Australia, is about 137 mm and the standard deviation is about…
A: The mean is 137 and the standard deviation is 69.
Q: A machine produces plastice bottles with a normally distrubted thickness of the plastic. The Mean…
A: Let X be the thickness of the plastic bottles which follows normal distribution with mean 4, and…
Q: H0:μ=58.455 H1:μ>58.455 Your sample consists of 46 subjects, with a mean of 58.8 and standard…
A: The random variable X is normally distributed. The sign of alternative hypothesis is greater than,…
Q: μ=42.895H0:μ=42.895 H1:μ≠42.895H1:μ≠42.895 Your sample consists of 22 subjects, with a mean of 42.4…
A: As the population standard deviation is not known, we will use t distribution.
Q: A population has mean =μ19 and standard deviation =σ5 . Find μx and σx for samples of…
A:
Q: Suppose X is a non-standard normal variable, with a mean of 120, and std deviation of 9 (i.e.…
A:
Q: What is the Discrete Variable Standard Deviation for the following numbers: x = 0 and P(X = x) =…
A: Answer:- Given the discrete variable is, x = 0 and P(X = x) = 0.56x = 1 and P(X = x) = 0.15x = 2 and…
Q: people who were playing roulette is 55.5 with a standard deviation of 3.2 years. Can it be concluded…
A: The random sample of people who were playing slot machines, The random sample of people who were…
Q: A simple random sample of six values had mean x = 13.00 and standard deviation s = 7.155. Calculate…
A: Given,
Q: ez-score for x = 61 is . So 61 is standard deviations (Choose one) ▼ the mean μ = 56. X
A: It is given thatMean, μ = 56Standard deviation, σ = 20Z-Score, Z = ( X - μ )/σwhere, Z be the…
Q: I researched the winning time for the 1/4 mile race in the Fayette County Fair. Let's assume that…
A: Given The winning times are normally distributed for both men and women. Let X be the winning times…
Q: A sample of 3000 observations has a mean of 88 and a standard deviation of 13. The distribution is…
A: Solution : Given: n = 3000 samples x¯ = 88 s = 13 For bell…
Q: A distribution of values is normal with a mean of 90 and a standard deviation of 5. Find the…
A: The provided information is µ=90 σ=5 P(-a<X<a)=0.02…
Q: Corey scores X = 70 on his first exam, for which the entire class scored a mean of µ = 78 and…
A: From the given information, let X be the Corey’s score on his first exam. X = 70. Mean score of the…
Q: A test score of 48.4 on a test having a mean of 66 and a standard deviation of 11. Find the z-score…
A:
Q: Ages of Gamblers The mean age of a sample of 25 people who were playing the slot machines is 49.9…
A: The Welch's t - test should be used to compare the mean differences between two population groups…
Q: H0:μ=29.345 H1:μ≠29.345 Your sample consists of 27 subjects, with a mean of 28.9 and standard…
A: It is given that the sample mean is 28.9 and the standard deviation is 1.91.
Q: A standard deviation of 0 implies: there is great variability in the data there is no variability in…
A: The standard deviation is a measure of variability of the data. The formula for the standard…
Q: A normal distribution has mean μ = 60 and standard deviation σ = 20. Find and interpret the z-score…
A: Step 1: State the given data: raw score, x = 75population mean, µ = 60population standard deviation,…
Q: The amount of annual snowfall in a certain mountain range is normally distributed with a mean of 75…
A:
Q: Find the standard deviation for the given data n- 48, Σίx, = 1620 , Σix? = 6640ο , ΣΧ-180 %3D O a.…
A: Given that, n = 48∑fixi=1620∑fixi2=66400∑xi=180
Q: Suppose X is a non-standard normal variable, with a mean of 110, and std deviation of 13 (i.e.…
A: The mean is 110 and the standard deviation is 13.
Q: A random variable is not normally distributed, but it is mound shaped. It has a mean of 18 and a…
A: GivenMean(μ)=18standard deviation(σ)=2sample size(n)=40
Q: Suppose that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally…
A: It is given that the mean is 3.3 and the X value is 5.9 units.
Q: Suppose the distribution of maximum monthly January temperatures in Canberra is normal with mean, μ…
A:
Q: H0:μ=27.7H0:μ=27.7 H1:μ<27.7H1:μ<27.7 Your sample consists of 20 subjects, with a mean of 27.3 and…
A:
Q: (a) Find the z-score for an IQ of 111, rounded to three decimal places. (b) Find the probability…
A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…
Q: Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard…
A: According to the given information, we have Given that pulse rates of women are normally…
Q: Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the…
A: Given data mean=69.0 inches standard deviation=2.8 inches x=79.7 inches
Q: Suppose that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally…
A: From the provided information, Mean (µ) = 3.2 Confidence level = 99% The Z critical value at 99%…
Q: The value for μ is 1,025. It is not 1,064
A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…
Q: The standard deviation in the pressure required to open a certain valve is known to be o=1.2 psi.…
A:
Q: Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard…
A: Answer:- Given, Pulse rates of women (X) are normally distributed with a mean, µ = 77.5 beats per…
Q: Suppose that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally…
A: Given that: Population mean, μ=3.2 To find: Standard deviation of the distribution of healthy…
Q: The mean age of a sample of 25 people who were playing the slot machines is 49.9 years, and the…
A: The random sample of people who were playing slot machines, The random sample of people who were…
Q: The value of n such that P pn-1 ,n>4 is 15.
A: Given that
Q: A distribution is given as X~U (2,10). What is the 75th percentile? What is the 40th percentile?…
A: It is given that the X follows Uniform distribution with a as 2 and b as 10. X ~ U (2, 10).
Q: In a random sample of 7 cell phones, the mean full retail price was $548.40 and the standard…
A:
Q: Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores…
A: The z-score:The z-score of a normally distributed random variable, X, with mean μ and standard…
Q: Suppose X is a non-standard normal variable, with a mean of 139, and std deviation of 15 (i.e.…
A: The mean and the standard deviations are 139 and 15, respectively.
Step by step
Solved in 2 steps with 2 images
- The lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 14 days. A distribution of values is normal with a mean of 267 and a standard deviation of 14. What percentage of pregnancies last fewer than 274 days? P(X < 274 days) Let XX represent the full height of certain species of tree. Assume that XX is normally distributed with a mean of 82.1 feet and a standard deviation of 47.9 feet.Find the probability that the full height of a randomly selected tree is greater than 154 feet. P(X>154)I need the answer as soon as possibleFind the z score for the below data Mu= 23 Population standard deviation = 4 Individual score X = 29? Round to two decimal places
- Suppose X is a non-standard normal variable, with a mean of 145, and std deviation of 10 (i.e. X~N(145,10)). You have an observation (z) on a standard normal scale (i.e. Z~N(0,1)). If z = 0.72, what is it on an X scale? Express your answer to two decimal places (ex: 123.45).Pulse rates of adult men are approximately normal with a mean of 70 and a standard deviation of 8. Which choice correctly describes how to find the proportion of men that have a pulse rate greater than 78? (a) Find the area to the right of z = -1 under a standard normal curve. (b) Find the area to the right of z=1 under a standard normal curve. (c) Find the area to the left of z = 1 under a standard normal curve. (d) Find the area between z=-1 and z=1 under a standard normal curve. (e) None of the aboveSuppose X is a non-standard normal variable, with a mean of 122, and std deviation of 15 (i.e. X~N(122,15)). You have an observation (z) on a standard normal scale (i.e. Z~N(0,1)). If z = -1.39, what is it on an X scale? Express your answer to two decimal places (ex: 123.45).
- number 7 and 8 plsIQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual is randomly chosen. Let X = IQ of an individual. (a) Find the z-score for an IQ of 99, rounded to three decimal places. (b) Find the probability that the person has an IQ greater than 99. (c) Shade the area corresponding to this probability in the graph below. (Hint: The x- axis is the z-score. Use your z-score from part (a), rounded to one decimal place). Shade: Left of a value -1 -1.5 0 +). Click and drag the arrows to adjust the values. 1 2 (d) MENSA is an organization whose members have the top 2% of all IQs. Find the minimum IQ needed to qualify for the MENSA organization. (e) Sketch the graph, and write the probability statement. Edit Insert Formats B I U x₂ x² A => EM e & N 18 (f) The middle 50% of IQs fall between what two values? (g) Sketch the graph and write the probability statement. Edit Insert Formats BIUX₂ X² A E = = E EC P R N • Σ+ Σ Α Σ+ Σ ΑH0:μ=41.92H0:μ=41.92H1:μ≠41.92H1:μ≠41.92Your sample consists of 43 subjects, with a mean of 42 and standard deviation of 1.56.Calculate the test statistic, rounded to 2 decimal places. t=
- H0:μ=38.935H0:μ=38.935H1:μ≠38.935H1:μ≠38.935Your sample consists of 31 subjects, with a mean of 38.5 and standard deviation of 4.13.Calculate the test statistic, rounded to 2 decimal places. t=t=Suppose that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally distributed with a mean of 3.2 units/mL. Suppose also that exactly 98% of healthy individuals have TSH levels below 6.1units/mL. Find the standard deviation of the distribution of TSH levels of healthy individuals. Carry your intermediate computations to at least four decimal places. Round your answer to at least two decimal places.