IQ is normally distributed with a mean of 100 and a standard deviation of 15. Supposeone individual is randomly chosen. Let X = IQ of an individual.(a) Find the z-score for an IQ of 99, rounded to three decimal places.(b) Find the probability that the person has an IQ greater than 99.(c) Shade the area corresponding to this probability in the graph below. (Hint: The x-axis is the z-score. Use your z-score from part (a), rounded to one decimal place).Shade: Left of a value-1-1.50+). Click and drag the arrows to adjust the values.12(d) MENSA is an organization whose members have the top 2% of all IQs. Find theminimum IQ needed to qualify for the MENSA organization.(e) Sketch the graph, and write the probability statement.Edit Insert Formats B I U x₂ x² A=> EM e & N18(f) The middle 50% of IQs fall between what two values?(g) Sketch the graph and write the probability statement.Edit Insert Formats BIUX₂ X² AE = = E EC P R N•Σ+ Σ ΑΣ+ Σ Α

As per our guidelines we are suppose to answer only three sub parts. Given,Mean(μ)=100Standard…

Answered: IQ is normally distributed with a mean…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standarthed deviation of 15 0.6 the indicated IQ score, x is ________. Round to one decimal place as needed.
Find the indicated IQ score The graph to the right depicts IQ scores of adults in the scores are normally distributed with a mean of 100 and a standard deviation of 15The indicated IQ score, X is
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table, Click to view page 2 of the table. Step 1 теan(u) s tan dard o 90 115 The area of the shaded region is (Round to four decimal places as needed.) Step 2 Required pr X-µ = P = P (Z < 1 = P (Z < 2 = 0.9773 Enter your answer in the answer box and then click Check Answer. %3D All parts showing Clear All Final Check P Type here to search hp
A manufacturer of light bulbs finds that one light bulb model has a mean life span of 1025 h with a standard deviation of 83 h.Find the z-scores for lightbulbs which last 850 and 900 h. (Round your answers to two decimal places.) 850 h: z = 900 h: z =
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IQ tests supposedly measure our intelligence. They typically are ‘normed’ so that they have a mean of 100 and a standard deviation of 15. (Higher scores show higher intelligence.) Use the graph and use the z-score and percents from columns b and c in Table A, when relevant. If you scored 132, what is your z-score? (Interpret.) Use table A X, z(a), (b), and (c) X z (a) (b) (c) and use the graph! Write down or save your response to use in Part 2 of this quiz. Group of answer choices -2.53 z. I'm at the 98.34 percentile rank and 1.66% of people scored smarter than me. 2.13 z. I'm at the 98.34 percentile rank and 1.66% of people scored smarter than me. -2.13 z. I'm at the 1.66 percentile rank and 98.34% of people scored smarter than me. 2.53 z. I'm at the 0.57 percentile rank and 99.43% of people scored smarter than me. 2.13 z. I'm at the 1.66 percentile rank and 98.34% of people scored smarter than me. 2.53 z. I'm at the 99.43 percentile rank…
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. The indicated IQ score is (Round to the nearest whole number as needed.) X 0.1753
The Z-score tells you the number of standard deviations away from the mean (and in what direction) a data value is. The formula: Z = *- can be used to find the Z-score for a single member of the population. Notice X - μ tells you the signed distance the data value (X) is from the mean. When you divide that by the size of each chunk (the standard deviation) you are measuring the distance in units of the size of the standard deviations (how many standard deviations fit in the distance between the data value and the mean) - which gives you the Z-score. The formula X = μ+Z.o can be used to find the value in the population when given the Z-score (signed number of standard deviations). Notice that Z. tells you how far from the mean the data value is (since Z is the number of standard deviations and is the size of each standard deviation the product tells the total distance). So adding the distance from the mean to the mean gives the location along the number line for the data value. A…

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