141480 4. A student needs to prepare a buffer solution with a pH of 5.59. Assuming a pka of 4.54, how many mL of 0.1 M NaOH would need to be added to 24.0 mL of 0.1 M HB to prepare this buffer? Please include a proper (abbreviated) unit. HINT: Use pH = pKa + log ([B-]/[HB]) or, if concentrations are the same, pH = pka + log (Volume of OH-/ (Volume of HB - Volume of OH-) mis

141480 4. A student needs to prepare a buffer solution with a pH of 5.59. Assuming a pka of 4.54, how many mL of 0.1 M NaOH would need to be added to 24.0 mL of 0.1 M HB to prepare this buffer? Please include a proper (abbreviated) unit. HINT: Use pH = pKa + log ([B-]/[HB]) or, if concentrations are the same, pH = pka + log (Volume of OH-/ (Volume of HB - Volume of OH-) mis

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please don't provide handwritten solution... A 1.0 L solution contains 0.100 mol HC2H3O2 and 0.100 mol NaC2H3O2. The value for Ka HC2H3O2 is 1.8 X 10-5. What is the pH of the buffer after adding 0.010 mol NaOH to the buffer.
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A student needs to prepare a buffer solution with a pH of 4.60. Assuming a pK a of 4.12, how many mL of 0.1 M B minus would need to be added to 20.0 mL of 0.1 M HB prepare this buffer? Please include a proper (abbreviated) unit.HINT : Use pH = pK a + log ([B minus]/[HB]) or, if concentrations are the same, pH = pK a + log (Volume of B minus / Volume of HB)
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A student needs to prepare a buffer solution with a pH of 4.18. Assuming a pKa of 4.69, how many mL of 0.1 M NaOH would need to be added to 15.0 mL of 0.1 M HB to prepare this buffer? Please include a proper (abbreviated) unit. HINT : Use pH = pKa + log ([B minus]/[HB]) or, if concentrations are the same, pH = pKa + log (Volume of OH minus/ (Volume of HB minus Volume of OH minus)
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