14. The balanced equation below represents the reaction of KOH with H3PO4. KOH(aq) + H3PO4(aq) à KH2PO4(aq) + H2O(l) When 20 grams of KOH (56 g/mol) reacts with 49 grams of H3PO4 (98g/mol)How many grams of KH2PO4 (136g/mol) are produced? (First Find LR) 14. The balanced equation below represents the reactionof KOH with H,PO4.КОН(aq) + H,РО,(аq) ӑ КН,РО,(аq) +H,O(1)When 20 grams of KOH (56 g/mol) reacts with 49grams of H,PO4 (98g/mol)How many grams of KH,PO, (136g/mol) areproduced? (First Find LR)

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Answered: 14. The balanced equation below…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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14. The balanced equation below represents the reaction of KOH with H3PO4. KOH(aq) + H3PO4(aq) à KH2PO4(aq) + H2O(l) When 20 grams of KOH (56 g/mol) reacts with 49 grams of H3PO4 (98g/mol) How many grams of KH2PO4 (136g/mol) are produced? (First Find LR)

14. The balanced equation below represents the reaction
of KOH with H,PO4.
КОН(aq) + H,РО,(аq) ӑ КН,РО,(аq) +
H,O(1)
When 20 grams of KOH (56 g/mol) reacts with 49
grams of H,PO4 (98g/mol)
How many grams of KH,PO, (136g/mol) are
produced? (First Find LR)

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