Identify OA(Oxidant) and RA (Reductant) in the following reaction. CHĄ(g) + 2 02(g) CO2(g) + 2 H20(g) O OA=CH4 RA= CO2 OA=CH4 RA=O2 OA=H20 О ОА-Н20 RA= CO2 O RA=CH4 OA=O2

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Chapter1: Chemical Foundations
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Identify OA(Oxidant) and RA (Reductant) in
the following reaction.
CH4(g) + 2 02(g)
CO2(g) + 2 H20(g)
O OA=CH4
RA= CO2
O OA=CH4
RA=O2
O OA=H20
RA= CO2
O RA=CH4
OA=O2
Transcribed Image Text:Identify OA(Oxidant) and RA (Reductant) in the following reaction. CH4(g) + 2 02(g) CO2(g) + 2 H20(g) O OA=CH4 RA= CO2 O OA=CH4 RA=O2 O OA=H20 RA= CO2 O RA=CH4 OA=O2
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