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14. Let X₁, X2,..., X133 be independent normally distributed random variables with mean 30 and standard deviation 7.4. Let X = 133 (X₁ + X2+...+ X133). Let Q₁ be the mean of X and Q2 the standard deviation of X. Let Q = ln(3+|Q₁| +2|Q2|). Then T = 5 sin² (1000) satisfies:- (A) 0 ≤ T < 1. (B) 1 ≤ T < 2. (C) 2 ≤ T <3. - (D) 3≤ T < 4. (E) 4 ≤ T ≤ 5. -

14. Let X₁, X2,..., X133 be independent normally distributed random variables with mean 30 and standard deviation 7.4. Let X = 133 (X₁ + X2+...+ X133). Let Q₁ be the mean of X and Q2 the standard deviation of X. Let Q = ln(3+|Q₁| +2|Q2|). Then T = 5 sin² (1000) satisfies:- (A) 0 ≤ T < 1. (B) 1 ≤ T < 2. (C) 2 ≤ T <3. - (D) 3≤ T < 4. (E) 4 ≤ T ≤ 5. -

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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133 14. Let X₁, X2,..., X133 be independent normally distributed random variables with mean 30 and standard deviation 7.4. Let X = ¡(X₁ + X₂ + ... + X133). Let Q₁ be the mean of X and Q2 the standard deviation of X. Let Q = ln(3+|Q1| +2|Q2]). Then T = 5 sin² (1002) satisfies:- (A) 0 ≤ T < 1. (B) 1 ≤ T < 2. (C) 2≤ T <3. - (D) 3 ≤ T < 4. (E) 4 ≤ T ≤ 5. -
Transcribed Image Text:133 14. Let X₁, X2,..., X133 be independent normally distributed random variables with mean 30 and standard deviation 7.4. Let X = ¡(X₁ + X₂ + ... + X133). Let Q₁ be the mean of X and Q2 the standard deviation of X. Let Q = ln(3+|Q1| +2|Q2]). Then T = 5 sin² (1002) satisfies:- (A) 0 ≤ T < 1. (B) 1 ≤ T < 2. (C) 2≤ T <3. - (D) 3 ≤ T < 4. (E) 4 ≤ T ≤ 5. -
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