14. Based on the 95% Cl of (35.25193, 38.87857), which of the following values is plausible for a p- value?
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- A marketing manager fora cell phone company claims that the percentage of children aged 8-12 who have cell phones differs from 61%. In a survey of 826 children aged 8-12 by a national consumers group, 545 of them had cell phones. Can you conclude that the managers claim is true? Use the a = 0.10 level of significance and the p value method with the ti 84 plus calculator. Compute the p value. Round the answers to at least four decimal places.A random sample of leading companies in South Korea gave the following percentage yields based on assets. 2.4 1.9 4.6 1.2 0.1 3.6 2.4 0.2 1.7 1.8 1.4 5.4 1.1 Use a calculator to verify that s2 ≈ 2.479 for these South Korean companies.Another random sample of leading companies in Sweden gave the following percentage yields based on assets. 2.2 3.3 3.3 1.4 3.7 2.8 2.3 3.5 2.8 Use a calculator to verify that s2 ≈ 0.546 for these Swedish companies.Test the claim that the population variance of percentage yields on assets for South Korean companies is higher than that for companies in Sweden. Use a 5% level of significance. How could your test conclusion relate to an economist's question regarding volatility of corporate productivity of large companies in South Korea compared with those in Sweden? (a) What is the level of significance? (b) Find the value of the sample F statistic. (Use 2 decimal places.)What are the degrees of freedom? dfN dfDA random sample of leading companies in South Korea gave the following percentage yields based on assets. 2.3 2.2 4.1 1.5 0.9 3.6 2.4 0.2 1.7 1.8 1.4 5.4 1.1 Use a calculator to verify that s2 ≈ 2.025 for these South Korean companies.Another random sample of leading companies in Sweden gave the following percentage yields based on assets. 2.4 3.7 3.7 1.6 3.7 2.8 2.3 3.5 2.8 Use a calculator to verify that s2 ≈ 0.573 for these Swedish companies.Test the claim that the population variance of percentage yields on assets for South Korean companies is higher than that for companies in Sweden. Use a 5% level of significance. How could your test conclusion relate to an economist's question regarding volatility of corporate productivity of large companies in South Korea compared with those in Sweden? (a) What is the level of significance?State the null and alternate hypotheses. Ho: ?12 = ?22; H1: ?12 > ?22Ho: ?12 > ?22; H1: ?12 = ?22 Ho: ?22 = ?12; H1: ?22 >…
- The following table shows the results of a screening test hypothesized to identify persons at risk for a rare blood disease. Compute the False Positive Fraction of the test. No Disease Disease Screen Negative 1351 20 Screen Positive 39 41A humane society claims that less than 61% of households in a certain country own a pet. In a random sample of 700 households in that country, 399 say they own a pet. At a= 0.05, is there enough evidence to support the society's claim? Complete parts (a) through (c) below. (a) Identify the claim and state H, and Ha. Identify the claim in this scenario. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) O A. The percentage households in the country' that own a pet is not %. O B. Less than % of households in the country own a pet. O C. More than % of households in the country own a pet. O D. % of hoúseholds in the country own a pet.What is the cumulative frequency of students that scored half of the points on the SAT? choices: 1. none of the above/can't be determined 2. 26 3. 9 4. 55.5 5. 0.35 I already tried 2(26) and 5(0.35) but it was wrong.
- The control department of a light bulb manufacturer randomly picks 4400 light bulbs from the production lot every week. The records show that, when there is no malfunction, the defect rate in the manufacturing process (due to imperfections in the material used) is 1%. When 1.25%o or more of the light bulbs in the sample of 4400 are defective, the control unit calls repair technicians for service. Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of p, where p is the proportion of defective light bulbs in a sample of 4400 when there is no malfunction. (b) Find the standard deviation of p. (c) Compute an approximation for P(p N 0.0125), which is the probability that the service technicians will be called even though the system is functioning properly. Round your answer to four decimal places.Express each of your first five answers as a decimal and round to the nearest 0.001 (in other words, type 0.123, not 12.3% or 0.123456).What fraction of survey respondents identified themselves as Democrats? What fraction of survey respondents thought the economy was getting better? What fraction of Democrats thought the economy was getting better?A food company is planning to market a new kind of cereal; however before, they want to find the % of people who will like it. They select a random sample of 500 people and ask them to try the cereal. Of 500, 290 people say they like it. Compute the 95% cofidence interval for the % of the pop. that will like the cereal. Interept this cofidence interval.
- The following table shows the results of a screening test hypothesized to identify persons at risk for a rare blood disease. Compute the False Positive Fraction of the test. No Disease Disease Screen Negative 1274 28 Screen Positive 51 457.88 Aluminum cans contaminated by fire. A gigantic NW warehouse located in Tampa, Florida, stores approxi- mately 60 million empty aluminum beer and soda cans. Recently, a fire occurred at the warehouse. The smoke from the fire contaminated many of the cans with black- spot, rendering them unusable. A University of South Florida statistician was hired by the insurance com- pany to estimate p, the true proportion of cans in the warehouse that were contaminated by the fire. How many aluminum cans should be randomly sampled to estimate the true proportion to within .02 with 90% confidence?In an experiment, two different species of flowers were crossbred. The resulting 217 flowers from this crossbreeding experiment were categorized by the color of the flower and the stigma. The table provides the study results. 1: Magenta flower with Green stigma 2: Magenta flower with Red stigma 3: Red flower 4: Red flower Flower Type with Green stigma with Red stigma Observed # Flowers 115 49 32 21 According to genetic theory, the four resulting flower types should follow the ratio of 9:3:3:1, that is, should follow the following population proportions of 0.5625, 0.1875, 0.1875, and 0.0625. The biologist is interested in assessing whether the distribution for flower type for the experiment matches these genetic theory rates. The hypotheses to be tested are Họ: P1 = 0.5625, p2 = 0.1875, P3 = 0.1875, p4 = 0.0625, where p; represents the proportion of flowers in the population in group i HA: at least one p; differs from the stated proportions