13 11 9 7 5 3 1 0 Titration of 10.0mL of an unknown diprotic acid with 1.00M NaOH. 5 pH = 4.01 15 pH=9,27 10 Using the titration curve shown above: 1. Calculate the concentration of the acid using the data from equivalence point #1. 20 5. Calculate the value of pKal using the data from 3.0mL. 25 6. Calculate the value of pKa2 from the data at 17.0mL. 2. Calculate the concentration of the sulfurous acid using the data from equivalence point #2. 3. Calculate the volumes for midpoint #1 and midpoint #2. 4. Calculate the value of pKal from midpoint #1 and pKa2 from midpoint #2. 30
13 11 9 7 5 3 1 0 Titration of 10.0mL of an unknown diprotic acid with 1.00M NaOH. 5 pH = 4.01 15 pH=9,27 10 Using the titration curve shown above: 1. Calculate the concentration of the acid using the data from equivalence point #1. 20 5. Calculate the value of pKal using the data from 3.0mL. 25 6. Calculate the value of pKa2 from the data at 17.0mL. 2. Calculate the concentration of the sulfurous acid using the data from equivalence point #2. 3. Calculate the volumes for midpoint #1 and midpoint #2. 4. Calculate the value of pKal from midpoint #1 and pKa2 from midpoint #2. 30
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Titration of 10.0 mL of an Unknown Diprotic Acid with 1.00M NaOH**
*Graph Description:*
The graph shows a titration curve with pH on the y-axis and volume in milliliters (mL) of NaOH added on the x-axis. The curve starts at a low pH and rises sharply, indicating two distinct equivalence points.
- At around 5 mL, the pH is approximately 4.01.
- At around 23 mL, the pH is approximately 9.27.
*Task Instructions:*
1. Calculate the concentration of the acid using the data from equivalence point #1.
2. Calculate the concentration of the sulfurous acid using the data from equivalence point #2.
3. Calculate the volumes for midpoint #1 and midpoint #2.
4. Calculate the value of pKa1 from midpoint #1 and pKa2 from midpoint #2.
5. Calculate the value of pKa1 using the data from 3.0 mL.
6. Calculate the value of pKa2 from the data at 17.0 mL.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f4c86b2-1247-4388-bf18-f90827f5643c%2Fb0b480ec-872f-44f7-a084-d97e427a5ed7%2Fxbwy2i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Titration of 10.0 mL of an Unknown Diprotic Acid with 1.00M NaOH**
*Graph Description:*
The graph shows a titration curve with pH on the y-axis and volume in milliliters (mL) of NaOH added on the x-axis. The curve starts at a low pH and rises sharply, indicating two distinct equivalence points.
- At around 5 mL, the pH is approximately 4.01.
- At around 23 mL, the pH is approximately 9.27.
*Task Instructions:*
1. Calculate the concentration of the acid using the data from equivalence point #1.
2. Calculate the concentration of the sulfurous acid using the data from equivalence point #2.
3. Calculate the volumes for midpoint #1 and midpoint #2.
4. Calculate the value of pKa1 from midpoint #1 and pKa2 from midpoint #2.
5. Calculate the value of pKa1 using the data from 3.0 mL.
6. Calculate the value of pKa2 from the data at 17.0 mL.
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